Balance the Equation Hydrogen Sulphide Gas Burns in air to give Water and Sulphur Dioxide

Answer: Hydrogen sulphide gas burns in air to give water and sulphur dioxide can be expressed as :

H₂​S(g) + O₂​​(g)→H₂​​O(l) + SO₂​(g)

To balance this equation, you’re required to write the unbalanced chemical equation. After that, note down the number of atoms of each element that is present on both the reactant side as well as product side. Further, add coefficients to balance the mass in the given chemical equation.

Example :

1. 2H₂O means 4 Hydrogen atoms along with 2 oxygen atoms.
2. The first step includes balancing the single element of the oxygen atom and then coming to Hydrogen.
3. Here, first sulphur and oxygen will be balanced.
4. Utilize trial and error methods. Add 2 Hydrogen on both the sides, then it will turn out to be 4 on reactants side as well as on product side.
5. So 2H makes sense.
6. Use the same trial and error method to balance oxygen.
7. Adding 2 on both the sides, it will become 6 oxygen atoms on the reactant side along with 6 oxygen atoms on the product side.
8. Finally, the balanced chemical equation will be :

2H₂S + 3O₂ → 2SO₂ + 2H₂O