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Coordination compounds are molecules that are ligand-bound and include one or more metal centers (atoms, ions, or molecules that donate electrons to the metal). These chemicals can be either charged or neutral. When the complex is charged, it is stabilized by nearby counter-ions. A metal ion is in the center of a complex ion, which is surrounded by other molecules or ions. These are considered to be connected to the center ion via coordinate (dative covalent) bonds, however the bonding is occasionally more complicated. Ligands are molecules or ions that encircle the metal ion
1. The sum of the metal M’s coordination number and oxidation number in the complex [M(en)2 C204]. They’re
(a) 7
(b) 8
(c) 9
(d) 6
Answer/Explanation
Answer: (c) 9
Explanation: (c) 6 + 3 = 9
- At 25°C, which of the following will not give a positive test for Cl– with AgNO3(aq)?
(a) COCl3.5NH3
(b) COCl3.6NH3
(c) COCl3.3NH3
(d) COCl3.4NH3
Answer/Explanation-:
Explanation:(c) [CO(NH3)3Cl3) or COCl3.3NH3
does not have counter ions, so will not react with AgNO3(aq) .
3.Which of the following claims regarding [CO(CN)6]3- is correct
(a) It has 4 unpaired electron, high spin
(b) No unpaired electron, high spin
(c) No unpaired electron, low spin
(d) 4 unpaired electron, low spin
Answer: (c) No unpaired electron, low spin
Explanation:
(c) [CO(CN)6]3- has d²sp³hybridisation, no unpaired electrons and has low spin.
- When AgNO3 in excess is treated with complexes: COCl3.6NH3 , COCl3.5NH3 and C0Cl3.4NH3, the right order of the stoichiometries of AgCl produced is COCl3.6NH3, C0Cl3.5NH3, and C0Cl3.4NH3, respectively.
(a) 3AgCl, lAgCl, 2AgCl
(b) 3AgCl, 2AgCl, 1AgCl
(c) 2AgCl, 3AgCl, 2AgCl
(d) lAgCl, 3AgCl, 2AgCl
Answer: (b) 3AgCl, 2AgCl, 1AgCl
Explanation:
(b) [Co(NH3)6Cl3], [CO(NH3)5Cl] Cl2,
[CO(NH3)4Cl2], will form 3AgCl, 2AgCl and lAgCl respectively.
- Identify the right statement in relation to [Mn(CN)J2-] is
(a) It is sp²d² hybridized, tetrahedral
(b) It is d²sp³ hybridized, octahedral
(c) It is dsp² hybridized, square planar
(d) It is sp3d² hybridized octahedral
Answer: (b) It is d²sp³ hybridized, octahedral
Explanation: (b) d²sp³ inner orbital complex is present.
- Isomerism in the face and along the meridian will be demonstrated
(a) [Co(NH3)3Cl3]
(b) [Co(NH3)4Cl2] Cl
(c) [Co(en)3] Cl3
(d) [Co(NH3)5Cl] Cl2
Answer: (a) [Co(NH3)3Cl3]
Explanation: (a) it will show fac-mer isomerism
7.Which of the following has the highest molar conductivity?
(a) [Pt(NH3)2 Cl2]
(b) [CO(NH3)4 Cl2] Cl
(c) K4[Fe(CN)6]
(d) [Cr(H2O)3] Cl3
Answer: (c) K4[Fe(CN)6]
Explanation: (c) it will have highest molar conductivity.
- (At No. Cr = 24, Mn = 25, Fe = 26, Co = 27) is the pair with the same magnetic moment.
(а) [Cr(H2O)2]2+and [CoCl4]2-
(b) [Cr(H2O)6]2+ and [Fe (H2O)6]2+
(c) [Mn(H2O)6]2+ and[Cr(H2O)6]2+
(d) [COCl4]2-and [Fe(H2O)6]2+
Answer: (b) [Cr(H2O)6]2+ and [Fe (H2O)6]2+
Explanation:
(b) [Cr(H2O)6]2+
has 4s°3d4 electronic configuration, and has four unpaired electrons. [Fe(H2O)6]2+ has 4s°3d6 and has four unpaired electrons in it.
- The correct order of field strength among the ligands NH3, en, CN, and CO is
(a) NH3 < en < CN– < CO
(b) CN– < NH3 < CO < en
(c) en < CN–< NH3 < CO
(d) CO < NH3< en < CN–
Answer/Explanation
Explanation: (a) is the correct order
10.The chelate effect is the stabilization of coordination molecules caused by chelation. Which of the following complex species is the most stable?
(a) [Fe(CO)5]
(b) [Fe(CN)6]3-
(c) [Fe(C2O4)3]3-
(d) [Fe(H2O)6]3+
Answer: (c) [Fe(C2O4)3]3-
Explanation:
(c) is most stable because C2O4–is a bidentate ligand.
- Coordination compounds exhibit isomerism due to the presence of ambidentate ligands. [Pd(C6H5)2(SCN)2] and [Pd(C6H5)2(NCS)2] are two types of palladium complexes.
(a) linkage isomers
(b) coordination isomers
(c) ionization isomers
(d) geometrical isomers
Answer: (a) linkage isomers
Explanation:
(a) SCN is ambidentate ligand, therefore it shows linkage isomerism.
- A chelating agent binds to a single metal ion with two or more donor atoms. Which of the following is a chelating agent and which is not?
(a) thiosulphato
(b) oxalato
(c) glycinato
(d) ethane-1, 2-diamine
Answer: (a) thiosulphato
Explanation:
(a) S2O32- (thiosulphato) ion is unidentate ligand and is not a chelating agent.
13.. IUPAC name of [Pt(NH3)3 Br (NO2) Cl] Cl is
(a) triammine chloro dibromide platinum (IV) chloride
(b) triammine chloridobromidonitrochloride- platinum (IV) chloride
(c) triammine bromido chlorido nitro platinum (IV) chloride
(d) triammine nitro chloro bromo platinum (IV) chloride
Answer: (c) triammine bromido chlorido nitro platinum (IV) chloride.
- Trunbull’s blue is
(a) Ferricyanide
(b) Ferrous ferricyanide
(c) Ferrocyanide
(d) Fe3[Fe(CN)6]4
Answer
Answer: (b) Ferrous ferricyanide
15.. Primary and secondary valency of Pt in [Pt(en)2Cl2] are
(a) 4, 4
(b) 4, 6
(c) 6, 4
(d) 2, 6
Answer: (d) 2, 6
16.Which of the following has magnesium?
(a) Chlorophyll
(b) Haemocyanin
(c) Carbonic anhydrase
(d) Vitamin B12
Answer: (a) Chlorophyll
17.Which of the following shall form an octahedral complex?
(a) d4 (low spin)
(b) d8 (high spin)
(c) d6 (low spin)
(d) All of these
Answer: (d) All of these
18.Mn, Fe, Co, and Ni I have atomic numbers of 25, 26, 27, and 28 respectively. Which of the outer orbital octahedral ‘complexes has the same number of unpaired electrons as the others?
(a) [MnCl6]3-
(b) [FeF6]3-
(c) [CoF6]3-
(d) [Ni(NH3)6]2+
Answer:(a) and (c).
Explanation:
(a) and (c).
Both have the same number of unpaired electrons.
