Raoult’s Law was proposed by the famous French chemist Francois Marie Raoult in 1887. During an experiment, the chemist found that when substances are mixed in a solution, the vapour pressure of that solution is simultaneously decreased. From this observation, Raoult explained the relationship between partial pressure and mole fractions of two different components.
The law has great importance in physical chemistry, and it is viewed as the law of thermodynamics. Let’s look at an in-depth study of Raoult’s Law as well as its importance and limitations.
According to Raoult’s law, the solvent’s partial vapour pressure in a mixture is always equal to the vapour pressure of the pure solvent, multiplied by its mole fraction in that solution. In simple terms, the vapour pressure of a solution depends on the mole fraction of the solute dissolved into the solution. That means when a substance is added to a solution, the vapour pressure of the solution will ultimately decrease.
It depends on two variables :
Mathematically, the law is written as
It is to be noted that when more than one solute is dissolved in the solution, each solvent’s component is added to the total pressure of the solution.
Suppose there are one solvent and two different types of solutes in a solution. Then, both components are volatile in nature.
So, here, Solvent = Component 1
Solute2 = Component 2
Solute3 = Component 3
For each component, the partial pressure will be
P¹ = P1⁰x¹
P² = P2⁰x² (P⁰ – vapour pressure of pure component)
P³ = P3⁰ x³
So, according to Dalton’s law of partial pressure, the total vapour pressure of the solution will be
(PT = P1 + P2 + P3)
Let’s see how Raoult’s law works in a binary solution.
There are two components, A and B
So, partial pressure will be
PA = P⁰A • xA
PB = P⁰B • xB
So, PT = PA + PB
= P⁰A xA + P⁰B xB
As we all know that the mole fraction = (xA + xB = 1)
Hence, P⁰A (1- xB) + P⁰B xB
Here, P⁰B = 0
Here, B means solute.
0 represents no vapour pressure.
So, PT = P⁰A xA + P⁰B xB
PT = P⁰A xA + 0
Thus, PT = PA
If there are adhesive or cohesive forces present in between two components, then deviations from this law can be worked. The deviations are of two types.
It occurs in a non-ideal solution when the vapour pressure is lower than that what is anticipated by the law. This implies negative deviation. It happens when the forces between molecules are stronger than the molecules in pure liquids.
For example: Solution of chloroform and acetone, solution of water and hydrochloric acid, etc. In both of these cases, hydrogen bonds create deviations.
It occurs when in a non-ideal solution, the vapour pressure is greater than what is predicted by the law. It happens when the molecular forces of two components (A-B) are weaker than the A-A or B-B interaction forces. Consequently, it is easier for molecule A to escape as compared to a pure solution.
For example: Solution of ethanol and acetone, solution of chloroform and ethanol, etc are considered as positive deviations.
The relationship between Raoult’s Law with other important laws is as follows:
X¹ = Y¹ Ptotal / P⁰1
Here,
X¹ = mole fraction of component 1 in the solution
Y¹ = mole fraction in the vapour phase
What we get from the equation is that in an ideal solution containing pure components, each and every substance will have a different vapour pressure. Moreover, in the gas phase, the substances will have a higher vapour pressure but the solution will have a lower vapour pressure.
Raoult’s Law and the colligative properties are discussed below.
There are certain limitations to Raoult’s law. They are as follows:
Raoult’s law plays a pivotal role in determining the nature as well as the properties of a solution. It has great implications in thermodynamics also. It measures the intermolecular strength of liquids, and by adding non-volatile solutes, it lowers the vapour pressure of the solution. Through this article, we have learned the important points regarding Raoult’s law. We have also discussed how this law works with the colligative properties of a solution.