Below-mentioned is the first 20 multiples of table 89.
89 | × | 1 | = | 89 |
89 | × | 2 | = | 178 |
89 | × | 3 | = | 267 |
89 | × | 4 | = | 356 |
89 | × | 5 | = | 445 |
89 | × | 6 | = | 534 |
89 | × | 7 | = | 623 |
89 | × | 8 | = | 712 |
89 | × | 9 | = | 801 |
89 | × | 10 | = | 890 |
89 | × | 11 | = | 979 |
89 | × | 12 | = | 1068 |
89 | × | 13 | = | 1157 |
89 | × | 14 | = | 1246 |
89 | × | 15 | = | 1335 |
89 | × | 16 | = | 1424 |
89 | × | 17 | = | 1513 |
89 | × | 18 | = | 1602 |
89 | × | 19 | = | 1691 |
89 | × | 20 | = | 1780 |
The result of multiplying consecutive natural integers by 89 is given by the table of 89, which is a multiplication table. This table is highly helpful for computations and problem solving
Tips to Study Table of 89
The multiplication table of 89 is known as the 89 times table in mathematics. The arithmetic procedures addition and multiplication can be used to build the table. To study the first 10 multiples of table 89 in two different ways, go to the table below:
The method listed below should be used to easily learn tables:
89×1 = 89 | 89 |
89×2 = 178 | 89 + 89 = 178 |
89×3 = 267 | 89 + 89 + 89 = 267 |
89×4 = 356 | 89 + 89 + 89 + 89 = 356 |
89×5 = 445 | 89 + 89 + 89 + 89 + 89 = 445 |
89×6 = 534 | 89 + 89 + 89 + 89 + 89 + 89 = 534 |
89×7 = 623 | 89 + 89 + 89 + 89 + 89 + 89 + 89 = 623 |
89×8 = 712 | 89 + 89 + 89 + 89 + 89 + 89 + 89 + 89 = 712 |
89×9 = 801 | 89 + 89 + 89 + 89 + 89 + 89 + 89 + 89 + 89 = 801 |
89×10 = 890 | 89 + 89 + 89 + 89 + 89 + 89 + 89 + 89 + 89 + 89 = 890 |
The table of 89 can be found via repeated addition, for example, 89 + 89 + 89 + 89 + 89= 445, which is 89x 5.
Students must regularly practise and recite the table in order to memorise it.
Characteristics of the Table of 89
- The results of the multiplication will be produced by adding the number in sequence.
- In the multiplication table of 89, two multiple consecutive products differ by 89.
- 89 is a prime number.
- Only 1 and 89 are factors of 89.
Solved Examples
1. Determine 89 times 5 plus 100.
Solution:
89 times 5 plus 100= 89 x 5+ 100
= 445+ 100
We get,
= 545
Hence, the value of 89 times 5 plus 100 is 545.
2. Determine the value by Subtracting 4000 from the result of adding five multiples of 89.
Solution:
The first five multiples of 89 are as follows:
89 x 1 = 89
89 x 2 = 178
89 x 3 = 267
89 x 4 = 356
89 x 5 = 445
Sum = 89 + 178 + 267 + 356 + 445 = 1068
Now, 4000 – 1068 = 2932
3. Determine the value by Subtracting 3000 from the result of adding seven multiples of 89.
Solution:
The first five multiples of 89 are as follows:
89 x 1 = 89
89 x 2 = 178
89 x 3 = 267
89 x 4 = 356
89 x 5 = 445
89 x 6 = 534
89 x 7 = 623
Sum = 89 + 178 + 267 + 356 + 445 + 534 + 623 = 2225
Now, 3000 – 2225 = 775