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Table of 67 represents the results of multiplying 67 by various whole or natural numbers. The multiplication table of 67 is the repeated addition of 67. For example, on adding 67 four times – 67 + 67 + 67 + 67 = 268. The table of 67 from numbers 1 to 20 is listed below.
Table of 67 up to 10
| 67 × 1 = 67 | 67 × 6 = 402 |
| 67 × 2 = 134 | 67 × 7 = 469 |
| 67 × 3 = 201 | 67 × 8 = 536 |
| 67 × 4 = 268 | 67 × 9 = 603 |
| 67 × 5 = 335 | 67 × 10 = 670 |
Table of 67 up to 20
| 67 × 11 = 737 | 67 × 16 = 1072 |
| 67 × 12 = 804 | 67 × 17 = 1139 |
| 67 × 13 = 871 | 67 × 18 = 1206 |
| 67 × 14 = 938 | 67 × 19 = 1273 |
| 67 × 15 = 1005 | 67 × 20 = 1340 |
Tips for Memorising a table of 67.
- One of the most common tricks students use is writing down the multiplication table of 67 from 1 to 20. Example: One time sixty-seven is 67, Two times sixty-seven is 126, Three times sixty-seven is 189, and so on.
- The second easy trick is skip counting, which is the practice of counting forward from 0. We repeatedly add the same Number to the prior Number to skip counting. For example, here, we will count adding 0 to 67. So, 0 + 67= 67, 67 + 67 = 134, 134 + 67 = 201 and so on.
- In the third trick the multiples of 67 can be obtained by adding the addition of multiples of the table of 6 with the tens digit of the multiples of 7 times tables starting from 2 to 10. The unit digit of the results of the 67 times table, on the other hand, is the same as the unit digit of the multiples of the 7 times table. Take a look at the table below for a better understanding.
| Table of 6 | Table of 7 | |
| 6 x 1 = 6 | 7 x 1 = 7 | 67 (12 + 1 = 13) |
| 6 x 2 = 12 | 7 x 2 = 14 | 134 (18 + 2 = 20) |
| 6 x 3 = 18 | 7 x 3 = 21 | 201 (24 + 2 = 26) |
| 6 x 4 = 24 | 7 x 4= 28 | 268 (30 + 3 = 33) |
| 6 x 5 = 30 | 7 x 5= 35 | 335 (36 + 4 = 40) |
| 6 x 6 = 36 | 7 x 6= 42 | 402 (42 + 4 = 46) |
| 6 x 7 = 42 | 7 x 7= 49 | 469 (48 + 5 = 53) |
| 6 x 8 = 48 | 7 x 8= 56 | 536 (54 + 6 = 60) |
| 6 x 9 = 54 | 7 x 9 = 63 | 603 (60 + 7 = 67) |
| 6 x 10 = 60 | 7 x 10 = 70 | 670 |
Solved Examples
1) Mihir sells 67 roses in a day. How many roses will he sell in three weeks?
Solution:
Three weeks = 21 days
Number of roses in a day = 67
Number of roses sold by Mihir in
3 weeks = 67 x 21
So, 67 x 21 = 1407.
Therefore, the number of roses sold by Mihir in 3 weeks will be 1407.
2) A classroom in a school has a total of 67 seats each. How many total seats are there in 9 classrooms?
Solution:
Number of seats in each classroom = 67
Number of seats in 9 classrooms = number of seats in one classroom x 9
=> 67 x 9 = 603
The total number of seats in 9 classrooms is 603.
3) 67 kilos of Barley is supplied in one day to a shop. How many kilos of Barley can be provided in one week?
Solution:
Barley supplied in one day = 67 kg.
Barley supplied in one week = Barley supplied in one day x 7 days
So, 67 x 7 = 469.
Therefore, 469 kg of Barley can be supplied in one week.
4) What is the value of four times 67 divided by 2 minus 20?
Three times 67 is 4 x 67 = 248
Now we have to find the value of four times 67 divided by 2 minus 20.
So, 268 2 – 20= 134 – 20
=> 134 – 20 = 114.
Therefore, the value of four times 67 divided by 2 minus 20 is 114.
