A table of 57 can be calculated by doing repeated addition, such as 57 + 57 + 57 + 57 = 228 (57× 4) for example.
Table of 57 up to 10
57 × 1 = 57 | 57 × 6 = 342 |
57 × 2 = 114 | 57 × 7 = 399 |
57 × 3 = 171 | 57 × 8 = 456 |
57 × 4 = 228 | 57 × 9 = 513 |
57 × 5 = 285 | 57 × 10 = 570 |
Table of 57 up to 20
57 × 11 = 627 | 57 × 16 = 912 |
57 × 12 = 684 | 57 × 17 = 969 |
57 × 13 = 741 | 57 × 18 = 1026 |
57 × 14 = 798 | 57 × 19 = 1083 |
57 × 15 = 855 | 57 × 20 = 1140 |
Tips for Memorizing a Table of 57
- Cover the first 20 multiples of 57 in the multiplication table of 57, which often only shows the first 10 multiples of 57.
- The multiples of 57 in the table are produced by adding 57 repeatedly. For instance, 57 times 3 results in 57 + 57 + 57 = 171. As a result, 57 x 3 Equals 171.
- You can add the number more than once to get multiples of 57. For instance, 57 + 57 = 114 (or 57 * 2 = 114), which can also be produced using addition.
- 57 + 57 + 57 = 171 can also be reached through addition, which is 57×3 = 171.
- 57 × 4 = 228, which may also be achieved by addition, 57 + 57 + 57 + 57 = 228.
- Any two successive multiples of 57 are divisible by each other by 57.
Solved Examples
1. Every day, a client purchases 4 melons. In 57 days, how many melons would the customer purchase?
Each day, the consumer purchases 4 melons. Accordingly, using the table of 57, the buyer purchased a total of 4 x 57 = 228 melons over 57 days.
2. Each day, Kimberly produces 20 cupcakes. In 57 days, how many cupcakes does she produce?
Each day, Kimberly produces 20 cupcakes. The total number of cupcakes produced over 57 days is 20 x 57, and 1140 cupcakes, according to the table of 57.
3. Per day Daniel jogs 2 miles. Determine how many miles she jogs in 57 days using the table of 57.
Every day, Daniel jogs two miles. Thus, 2 x 57 = 114 miles have been covered overall after 57 days.