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54 multiplied with any given number derives the 54 times table. The multiplication table of 54 can be computed by repeated addition of the multiples. For example, 54 times 3 can be calculated as 54+54+54, equal to 162, which is eventually 54×3. All multiples of 54 are even numbers.
Table of 54 up to 10
| 54 x 1 = 54 | 54 x 6 = 324 |
| 54 x 2 = 108 | 54 x 7 = 378 |
| 54 x 3 = 162 | 54 x 8 = 432 |
| 54 x 4 = 216 | 54 x 9 = 486 |
| 54 x 5 = 270 | 54 x 10 = 540 |
Table of 54 up to 20
| 54 x 11 = 594 | 54 x 16 = 864 |
| 54 x 12 = 648 | 54 x 17 = 918 |
| 54 x 13 = 702 | 54 x 18 = 972 |
| 54 x 14 = 756 | 54 x 19 = 1026 |
| 54 x 15 = 810 | 54 x 20 = 1080 |
Tips to Memorise Table of 54
- To memorise the table of 54 easily, one must regularly practice the table by effective recitation.
- One other way of memorising the table is by writing down the multiplication table of 54 from 1 to 20, like 54 times two is 108, 54 times three is 162 and 54 times four is 216 and so on.
- The easy way of remembering the table is repetitive addition. We add the same number repeatedly to the last number to get the next multiple. For instance, 54 + 54 = 108, which gives us 54 times 2, now we add 54 + 108 = 162, and this gives 54 times 3.
Solved Examples
1. If Sean bakes 7 doughnuts in a day. How many doughnuts will he bake in 54 days?
Solution:
Sean bakes 7 doughnuts in a day. Therefore, using the table of 54, The total number of doughnuts that Sean will bake in 54 days is 7 x 54 = 378.
2. A pit can carry 54 oranges. Calculate the total number of oranges in 15 such pits.
Solution:
Number of oranges in 1 pit = 54.
The number of oranges in 20 such pits = 54 x 20.
Therefore, the total number of oranges in 20 pits is 1080.
3. How much is 11 less than the 17th multiple of 54?
Solution:
Using the multiplication table of 54,
The 17th multiple of 54 is 918.
Now, 11 less than the 17th multiple of 54 is given as 918 – 11, which is equal to 907.
4. Sameera jogs about 5 kilometres every day. Calculate the total distance travelled in kilometres if she goes for a jog every day for 54 days, using the multiplication table.
Solution:
The distance covered in one day is 5km.
Using the multiplication table, the total distance covered can be given as 5 x 54.
Therefore the total distance covered in 54 days is 270 km.
