Profile
Settings
Refer your friends
Sign out
Multiplication Table of 33 represents the results of multiplying 33 by various whole or natural numbers. The multiplication table of 33 is the repeated addition of 33. For example, on adding 33 four times – 33 + 33 + 33 + 33 = 132. The Table of 33 from numbers 1 to 20 is listed below.
Table of 33 up to 10
|
33 × 1 = 33 |
33 × 6 = 198 |
|
33 × 2 = 66 |
33 × 7 = 231 |
|
33 × 3 = 99 |
33 × 8 = 264 |
|
33 × 4 = 132 |
33 × 9 = 297 |
|
33 × 5 = 165 |
33 × 10 = 330 |
Table of up to 20
|
33 × 11 = 363 |
33 × 16 = 528 |
|
33 × 12 = 396 |
33 × 17 = 561 |
|
33 × 13 = 429 |
33 × 18 = 594 |
|
33 × 14 = 462 |
33 × 19 = 627 |
|
33 × 15 = 495 |
33 × 20 = 660 |
Tips to memorise the Table of 33.
-
One of the most common tricks students use is writing down the multiplication table of 33 from 1 to 20. Example: One-time thirty-three is 33, Two times thirty-three is 66, Three times thirty-three is 99, and so on.
-
Another trick that can be applied is the addition of multiplication tables of 3 and 30 together. Take a look at the Table below.
|
Table of 3 |
Table of 30 |
Table of 33(sum of table of 3 and 30 with multiplication by respective numbers) |
|
3 x 1 = 3 |
30 x 1 = 30 |
3 x 1 = 3 + 30 x 1 = 30 i.e., 3 + 30 = 33 |
|
3 x 2 = 6 |
30 x 2 = 60 |
3 x 2 = 6 + 30 x 2 = 60 i.e., 6 + 60 = 66 |
|
3 x 3 = 9 |
30 x 3 = 90 |
3 x 3 = 9 + 30 x 3 = 90 i.e., 9 + 90 = 99 |
|
3 x 4 = 12 |
30 x 4 = 120 |
3 x 4 = 12 + 30 x 4 = 120 i.e., 12 + 120= 132 |
Solved Examples
1. Sara can solve two questions in a minute. Calculate how many questions she can solve in 33 minutes.
According to the question, the number of questions Sara solves in a minute is 2, so in 33 minutes, she will be able to solve: 2 x 33 = 66. Therefore, Sara can solve 66 questions in 33 minutes.
2. Subtract 150 by eight times 33.
From the multiplication table of 33 : 8 x 33 = 264.
Now, if we subtract 150 from 8 times 33, we get:
264 – 150 = 114.
Therefore, 114 is the answer.
3. A box fits 33 balls in it. How many packages will be required to hold 594 balls?
With the help of multiplication in Table of 33, we find out that 33 times 19, i.e., 33 x 18 = 594,
Therefore 18 boxes will be required to fit 594 balls.
4. What is 16 times 33 minus 140 plus 178?
With the help of multiplication in Table 33, we find out that 33 times 16, i.e., 33 x 16 = 528,
Now according to the question, we have to subtract 140 by the result of 16 times 33, so,
=> 528 – 140 = 388
=> 388 + 178 = 566
Therefore, 16 times 33 minus 140 plus 178 is 566.
