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The table of 100 represents the results of multiplying 100 by various whole or natural numbers. The multiplication table of 100 is the repeated addition of 100. For example, on adding 100 three times – 100 + 100 + 100 = 300. The table of 100 is the table of 1 with double 0 as the last digits, respectively.
Table of 100 up to 10
| 100 × 1 = 100 | 100 × 6 = 600 |
| 100 × 2 = 200 | 100 × 7 = 700 |
| 100 × 3 = 300 | 100 × 8 = 800 |
| 100 × 4 = 400 | 100 × 9 = 900 |
| 100 × 5 = 500 | 100 × 10 = 1000 |
Table of 100 up to 20
| 100 × 11 = 1100 | 100 × 16 = 1600 |
| 100 × 12 = 1200 | 100 × 17 = 1700 |
| 100 × 13 = 1300 | 100 × 18 = 1800 |
| 100 × 14 = 1400 | 100 × 19 = 1900 |
| 100 × 15 = 1500 | 100 × 20 = 2000 |
Tips for memorizing a table of 100.
- One of the most common tricks students use is writing down the multiplication table of 100 from 1 to 20. Example: One time hundred is 100, Two times hundred is 200, Three times hundred is 300 and so on.
- The second easy trick is skip counting, which is the practice of counting forward from 0. We repeatedly add the same number to the last number to skip counting. For example, here, we will count adding 0 to 100. So, 0 + 100= 100, 100 + 100 = 200, 200 + 100 = 300 and so on.
- Third simple trick is to write down the multiplication table of 1 with double 0 as their last digit as shown in the table below.
| Table of 1 | Adding two 0 as last digit |
| 1 x 1 = 1 | 100 |
| 1 x 2 = 2 | 200 |
| 1 x 3 = 3 | 300 |
| 1 x 4 = 4 | 400 |
Solved Examples
1)A delivery boy delivers a hundred orders in a week. How many orders will he deliver in three weeks?
Solution:
Number of orders delivered by
delivery boy in a week = 100
Number of orders delivered by
delivery boy in 3 weeks = 100 x 3
So, 100 x 3 = 300.
Therefore, the number of orders delivered by the delivery boy in 3 weeks will be 300.
2) Anuj scored 100 in all six subjects. What is his total score?
Solution:
The score of Anuj in each subject= is 100
Therefore his total score in all six subjects will be 100 x 6 = 600.
The total score of Anuj in all six subjects is 600.
3) Six metres of aluminium are required to make a tin box. How many meters of aluminium will be required to complete 100 tin boxes?
Solution:
Aluminium required to make a tin box = 6 metres
Aluminium required to make 100 tin boxes = 6 x 100
So, 6 x 100 = 600.
Therefore, the aluminium required to make 100 tin boxes is 600 meters.
4) What is the value of eight times 100 divided by 5 minus 120?
Solution:
Eight times 100 is 8 x 100.
So with the help of the tricks mentioned above, 8 x 100 = 800.
Now we have to find the value of eight times 100 divided by 5 minus 120.
So, 800 5 – 120 = 160 – 120
=> 160 – 120 = 40.
Therefore, the value of eight times 100 divided by 5 minus 120 is 40.
