By definition, a homogenous equation must have zero on the right side of the = sign. It varies from non-homogeneous equations as the latter has a function of the independent variable on the right-hand side of the equation. In calculus, homogeneous differential equations are simply the differential equations with a homogenous function. The homogeneous function is a function of multiple variables such that, if all the arguments are multiplied by a scalar, then the value of the function is multiplied by the power of that scalar. If a function f(x,y) is expressed by x = cx and y = cy to generate a new function f(cx, cy) = cn(x,y), such that the constant can be assumed as the nth power of the exponent, then the equation is homogeneous. An equation presenting the form of y(n) p(x). y^{(n)}. P(x) y(n)p(x) is termed as a homogeneous linear equation. Linear signifies that a derivative of y times x’s function while homogenous indicates 0 on the right side. A homogeneous equation always has a consistent solution because of zero. Some common homogeneous differential equation examples are provided below:
dy/dx = (x+y)/(x-y)
dy/dx = (x3 + y3)/(xy2 + yx2)
dy/dx = (3x + y)/(x –y)
Homogeneous Differential Equations
Johann Bernoulli proposed homogeneous differential equations in integration. Two ways by which a differential equation can be homogenous are:
- First-order equations are considered to be homogenous if, f(x,y)dy = m(x,y)dx
Here, f and m are homogenous functions of x and y. They have the same degree.
Similarly, dx/x = q (µ) dµ; as we change the variable y =µx. This will help to perform the integration.
- Secondly, a differential equation may be homogenous if it has the homogenous function of the present unknown functions and their derivatives.
According to Bernoulli, a first order differential equation M(x,y)dx + N(x,y)dy = 0 is homogenous if both the functions have equal degree n.
M(γx, γy) = γnM(x,y) = N(γx, γy)
Therefore, M(γx, γy)/N(γx, γy) = M (x,y)/N(x,y).
The problems can be solved using the method of separation of variables. Before that, we need to introduce a new variable.
We will see this in a simple example.
Problem:
dy/dx = x2 +y2 /xy
Solution:
We need to separate the terms on the right side, so:
x2 +y2 /xy
= x2 /xy + y2 /xy
=x/y + y/x
Using reciprocal method we can write:
(y/x)-1 + (y/x)
HERE WE GO, we have a function of (y/x).
Returning to the sum,
dy/dx = (y/x)-1 + (y/x)
Let us consider y = vx.
So, dy/dx = v + x.dv/dx: v + x.dv/dx = v-1 + v
x.dv/dx = v-1 [subtracting v from both ends]
In this stage we are going to implement separation of variables.
v dv = 1/x. dx
Integrating both ends, ∫v.dv = ∫1/x.dx
v2/2 = ln(x) + C
Let’s consider C = ln(k)
Therefore, v2/2 = ln(x) + ln(k)
Or, v2/2 = ln(kx)
Simplification will lead to:
v = ± √(2 ln(kx))
After putting back y/x, y/x = ± √(2 ln(kx))
Or, y = ± x√(2 ln(kx))
We have solved the equation.
Homogeneous Linear Equation
A system of the equation can be termed as homogeneous and linear given, the constant term is found to be zero.
C11x1 + C12x2 + … + C1nxn = 0 … 1
C21x1 + C22x2 + … + C2nxn = 0 … 2
Cm1x1 + Cm2x2 + … + Cmnxn = 0 … 3
A homogeneous equation is bound to have one obvious solution. Here, x1 = x2 = xn = 0 for all the above three equations.
To have infinite solutions, the value of n must be greater than m (n > m).
Also, we can conclude that there are (n-m) free variables that can uptake any value.
Problem
Solve 2y’’ – 5y’ – 3y = 0
Solution
Let us transform the equation into algebraic form by replacing y’’ with m2, y’ with m, and y with 1.
New equation: 2m2 – 5m – 3 = 0
The roots of this equation are – ½ and 3. This confirms that e-x/2 and e3x are two linearly independent solutions.
Finally, the general solution is presented as: y = C1 exp (-x/2) + C2 exp (3x)
Conclusion
In this article, we discuss the various ideas of solving homogeneous equations. We know that nonhomogeneous differential equations have terms involving x on the right side. This characteristic helps us to identify whether a DE is homogeneous or nonhomogeneous. Homogeneous linear equations with constant coefficients are given as: y’’ + by’ + cy = 0. The differential equation plays a role in modifying the output after we start with independent variables for specified inputs. The roots of homogeneous differential equations determine the general solution of the equation.