CSIR NET EXAM » CSIR UGC-NET Exam Study Materials » Mathematical Sciences » Differential Equation: Initial Value

Differential Equation: Initial Value

Understand the conditions and steps to solve the existence and uniqueness of solutions of initial value and its order of the differential equation.

Existence and Uniqueness of Solutions of Initial Value Problem

What is a Differential Equation?

A differential equation is an equation ddx=f(x) of the type that contains a derivative. Differential equations are a key concept in mathematics, engineering, and the sciences. Many of the equations you encounter in science and engineering are generated from a variety of differential equations known as an initial value issue.

Initial Value Problem

An initial value problem in multivariable calculus is an average differential equation with an initial condition that determines the value of the unknown function at a specific location in the domain. The modeling of a system in physics or other sciences requires generally approaching an approximation value problem.

Definition

A differential equation is used to solve an initial value problem 

y'(t)=f(t,y(t) with f:Ω⊂R×Rn→where Ω is an open set of R×Rn

together with a point in the domain of f

(t0,y0)∈Ω,

known as the initial condition.

A solution to an initial value problem is a function y that is a differential equation solution that satisfies

y(t0)=y0

The differential equation is replaced by a series of equations in higher dimensions y’i(t)=fi(t,y1(t),y2(t),……), and y(t) is seen as the vector y1(t),…..yn(t)),  most frequently connected with a position in space. In general, the unknown function y can accept values on infinite dimensional spaces like Banach spaces or distribution spaces. Initial value problems are stretched to higher orders by treating derivatives as independent functions.

An initial value problem is a challenge of finding a function y of x when we know its derivative and its value y0 at a specific point x0. This issue can be resolved in two ways.

  1. dy=f(x)dx→y=F(x)+c……….(General Equation)
  2. Plug the baseline information into the general solution and solve for c.

Existence and Uniqueness of Initial Value Problem

If f is continuous on a region encompassing t0 and y0 and satisfies the Lipschitz condition on the variable y, the Picard–Lindelöf theorem provides an optimal solution on some interval containing t0. This hypothesis is demonstrated by improving the issue into an identical vital condition. The essential can be considered as an administrator, which moves one capacity to another, whereby the determination is a decent brand of an administrator.

An earlier demonstration of the Picard–Lindelöf theorem generates a series of functions that converge to the solution of the integral equation, and hence to the answer of the initial value problem. This sort of construction is known as “Picard’s method” or “the method of successive approximations.” This variant is just a Banach fixed point theorem variant.

Hiroshi Okamura located a situation that is each vital and enough for a preliminary fee hassle strategy to be unique. This criterion is attached to the presence of a Lyapunov characteristic withinside the system.

In some circumstances, the function f is not of class C1, or even Lipschitz, and so the conventional conclusion ensuring the local existence of a unique solution does not follow.

The Peano existence theorem, on the other hand, establishes that even for f just continuous, solutions are guaranteed to exist locally in time; nevertheless, there is no guarantee of uniqueness. Coddington and Levinson or Robinson have the solution. A particularly extra trendy result is the Carathéodory life theorem, which proves life for precise discontinuous features f.

Theorem:

The existence and uniqueness theorem is a tool that allows us to conclude that there exists only one solution to a first-order differential equation that meets a certain initial condition.

Let f(x,y) be a real and continuous function on the rectangle

R={(x,y);|x-x0|≤a, |y-y0|≤b}

With respect to y, assume that f has a partial derivative and that ∂f∂y is continuous on the rectangle R. Then there survives I=[x0-h, x0+h] such that the initial value problem

y’=f(x,y)

y(x0)=y0

on interval I, there is only one solution y(x).

It should be noted that h could be less than a. Assume the conclusion is true in order to grasp the main ideas behind this theorem. Then, if y(x) solves the initial value problem, we must have

y(x)=y0+x0xf(t,y(t))dt

It is not difficult to show a function y(x) meets the functional equation.

y(x)=y0+x0xf(t,y(t))dt

It is the answer to the initial value problem if it falls on an interval I.

y’=f(x,y) y(x0)=y0

Picard was among the first to examine the corresponding functional equation. Picard’s iteration approach, often known as the method of repeated approximations, is the method he created to determine y. Here’s how it works:

  • Stage 1: Considering the constant function

y0(x)=y0

  • Stage 2: Define the function yn(x) once it is known. 

yn+1(x)=y0+x0xf(t,yn(t))dt

  • Stage 3: We build a sequence of functions {yn(x)} by induction that, under the conditions established on f(x,y), merges to the initial value issue solution y(x).

y’=f(x,y)  y(x0)=y0

Conclusion

In this module, we understand the existence and uniqueness of the initial value problem in the differential equation and the theorem derived. The differential initial value is an equation that describes how the system constantly changes given the initial circumstances of the problem.

faq

Frequently asked questions

Get answers to the most common queries related to the CSIR Examination Preparation.

What are differential equations?

Ans: A differential equation is an equation d...Read full

What are initial value problems?

Ans: An initial value problem in multivariable calculus is an average differential equation with an...Read full

How can we find the function of y and x?

Ans: An initial value problem is the challenge of finding a function y of x when we know its deriva...Read full