The standard form of a complex number is a + bi, where a and b are real numbers, a is called the real part, and b, the imaginary part. Rene Descartes first called ‘i’ the imaginary number because the equation cannot be satisfied by a real number. i always satiates the equation i2 = −1. If b ≠ 0, a + bi is also called a complex number. We use the letter C to refer to the set of all complex numbers. If an equation has no solution using real numbers, you can easily insert imaginary numbers into the same to get an answer.
Thus,
C = {a + bi}, a ∈ R and b ∈ R and i²= –1
The real and imaginary parts of a complex number C may be denoted by Re(C), and Im(C), respectively.
For example, if (i) z = 7 + 8i, then Re(z) = 7, Im(z) = 8
(ii) z = –√3 – 11i, then Re(z) = –√3, Im(z) = –11
For adding and subtracting complex numbers, we need to first combine the real parts of the complex numbers together and then proceed to combine the imaginary parts of the complex numbers together and then finally apply the operations.
When we seek to add complex numbers, we combine the real parts of the complex numbers separately and imaginary parts separately and add them. In a geometric plane, if you wish to add two complex numbers, it can be done with the construction of a parallelogram. The addition of complex numbers is carried out using the following formula:
x1 + x2 = a + iy + c + iz
= (a + c) + (iy + iz)
= (a + c) + i(y + z)
Hence we have (a + iy) + (c + iz) = (a + c) + i(y + z)
(2 + 4i) + ( 3 – 2i) = 2 + 4i + 3 – 2i = 2 + 3 + 4i – 2i = 5 + 2i
2. Add 3 + (–1 – 3i) + (4 + i) + (5 – 2i)
3 + (–1 – 3i) + (4 + i) + (5 – 2i) = 3 – 1 – 3i + 4 + i + 5 – 2i = 11 – 4i
3. Add (3 + √–49) + (9 – √–25)
(3 + √–49) + (9 – √–25) = (3 + 7i) + (9 – 5i)
= 3 + 7i + 9 – 5i = 3 + 9 + 7i – 5i = 12 + 2i
(–3 + 7i√3) + (9 – 2i√3) = –3 + 7i√3 + 9 – 2i√3
= –3 + 9 + 7i√3 – 2i√3 = 6 +5i√3
To subtract complex numbers, we separate the real and imaginary parts of the complex numbers and group them. Then we subtract the real and imaginary parts of one complex number from the real and imaginary parts, respectively, of the other complex number. Thus, subtraction of complex numbers is done by the following formula,
x1 – x2 = (a + iy) – (c + iz)
= a + iy – c – iz
= (a – c) + (iy – iz)
= (a – c) + i(y – z)
Thus we have (a + iy) – (c + iz) = (a – c) + i(y – z)
(6 + 3i) – (4 – 4i) = 6 + 3i – 4 – (–4i) = 6 – 4 + 3i + 4i = 2 + 7i
Rule grouping: (6 + 3i) – ( 4 – 4i ) = (6 – 4) + ( 3 – (–4) )i = 2 + 7i
= ( 4 – 4i ) – ( 12 – 13i )
= 4 – 4i – 12 + 13i = 4 – 12 – 4i + 13i = –8 + 9i
= 5 + 7√5i – 6 – 12√5i
= (5 – 6) + (7√5 – 12√5)i
= –1 – 5√5i
= ( 15 + 9i ) – ( 10 – 15i )
= 15 – 10 + 9i – (– 15i)
= ( 15 – 10 ) + ( 9 + 15 )i
= 5 + 24i
Thus the steps for adding and subtracting complex numbers are as follows :
Further,
Following are the properties of addition and subtraction of complex numbers:
(a+ib)+(c+id)=(c+id)+(a+ib)
(a+b)+c=a+(b+c)
Where a,b,c are complex numbers.