Sign up now
to enroll in courses, follow best educators, interact with the community and track your progress.
Questions : #29 & #30 (In Hindi)
45 plays

In this lesson we'll solve questions #29 & #30 from the question paper of IIT JEE MAINS 2017 - Set A

Kumar Ketan is teaching live on Unacademy Plus

Kumar Ketan
#6 years teaching experience #Physics Faculty in Kota #"magical education" (200k+ subs) #Follow for Physics of JEE NEET AIIMS etc. #Writer

Unacademy user
please continue Ma'm
Aartee Mishra
2 years ago
Thanks Thouseef
Thouseef V
2 years ago
Thanks to you Ma'm,Keep going
  1. ne

  2. 32.5k 4.8 unacademy views Kumar Ketan #14 Educator in IIT JEE Follow me on #6 years teaching experience #IIT JEE Physics #YouTuber "magical education"(160k+ subs) #Unacademy educator(31k+ lifetimeviews) #Under grad 1.6k 2 30 Followers Following Courses . Get updates about new courses . Watch all my lessons . Download slides and watch offline Lists (1) HINDI IIT JEE Q Kumar Ketan Physics by Kumar Ketan for IIT JEE 13 saves 2 Kumar Ketan

  3. IIT JEE 2017 PHYSICS Q. #1 to Q. #30 INDIAN IAN INSTITUTE Complete Paper Solution

  4. Question 29 Which of the following statements is false? 1) Wheatstone bridge is the most sensitive when all the four resistances are of the same order of magnitude 2) In a balanced Wheatstone bridge if the cell and the galvanometer are exchanged, the null point is disturbed 3) A rheostat can be used as a potential divider 4) Kirchhoff's second law represents energy conservation

  5. Sol. In a balanced Wheatstone bridge, the null point remains unchanged even if cell and galvanometer are interchanged.

  6. Question 30 The following observations were taken for determining surface tension T of water by capillary method; diameter of capillary, D1.25 x 10-2 m, rise of water, h-1.45 x 10-2 m. Using g-9.80 m/s2 and the simplified relation T x 103 N/m the possible error in surface tension is closest to (1) 0.15% (2) 1.5% (3) 2.4% (4) 10%

  7. AD Ah Sol. -x100=-x100 +- 100 0.01 1.25 100 100 125 145 0.01 1.45 x100x1 -0.8 0.689 = 1.489 1.5%