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Questions : #15 & #16 (In Hindi)
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In this lesson solve questions #15 & #16 from the question paper of IIT JEE MAINS 2017 - Set A

## Kumar Ketan is teaching live on Unacademy Plus

Kumar Ketan
#Specialisation in Electronics #6 years teaching experience #Physics Faculty in Kota #"magical education" (211k+ subs) #Writer

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THANKS sir,,, nice SESSION 🙋‍♀️🤗🤗👍👍👍👍👍👍
thank u sir...
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3. IIT JEE 2017 PHYSICS Q. #1 to Q. #30 INDIAN IAN INSTITUTE Complete Paper Solution

4. Question 15 A capacitance of 2uF is required in an electrical circuit across a potential difference of 1.0 kV. A large number of 1uF capacitors are available which can withstand a potential difference of not more than 300 V. The minimum number of capacitors required to achieve this is (2) 16 (3) 24 (4) 32

5. Sol. Following arrangement will do the needful 8 capacitors of 1 F in parallel with four such branches in series. 3 1000 V 250 V 250 V 250 V 250 V 1000 V

6. Question 16 In the given circuit diagram when the current reaches steady state in the circuit, the charge on the capacitor of capacitance C will be:|_www (1) CE (2) CE - (r2 +r) (3) CE 2 (4) CE 1 r +r2)

7. Sol. In steady state, flow of current through capacitor will be zero. r. r +r 2 Er, r+r ir,C = 2

8. Question 17 2 V 2 V 2 V 1 1 1 2 V 2 V 2 V In the above circuit the current in each resistance is (1) 1 A (2) 0.25 A (3) 0.5 A (4) 0 A

9. Sol. The potential difference in each loop is zero. . No current will flow.

10. Question 18 A magnetic needle of magnetic moment 6.7 10-2 Amp and moment of inertia 7.5 10-6 kg m2 is performing simple harmonic oscillations in a magnetic field of 0.01 T. Time taken for 10 complete oscillations is (1) 6.65 s (2) 8.89 s (3) 6.98 s (4) 8.76 s

11. Question 19 When a current of 5 mA is passed through a galvanometer having a coil of resistance 15 , it shows full scale deflection. The value of the resistance to be put in series with the galvanometer to convert it into a voltmeter of range 0-10 V is (1) 1.985 x 1030 (2) 2.045 x 1030 (3) 2.535 x 103n (4) 4.005 x 1030

12. Question 20 In a coil of resistance 100 0, a current is induced by changing the magnetic flux through it as shown in the figure. The magnitude of change in flux through the coil is 10 Current (amp.) (1) 200 Whb (2) 225 Wb (3) 250 Wb (4) 275 Whb 0.5 s Time

13. Sol. In X-ray tube hc in eV hc Slope is negative Intercept on y-axis is positive log in log V