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Important Previous years questions of IIT JEE Part - 6 (In Hindi)
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Through this lesson, you can learn the solution of some advanced level questions which has asked in previous years exams of IIT JEE.

Kumar Ketan is teaching live on Unacademy Plus

Kumar Ketan
#Specialisation in Electronics #6 years teaching experience #Physics Faculty in Kota #"magical education" (211k+ subs) #Writer

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sir biology ki tricks pr video banao specially morphology plzzzz sir
  1. 0 minutes today Home ExplorelSearch Courses, Topics & Educators Kumar Ketan Hey, this is kumar Ketan. I'm graduate in physics and doing further studies. I Edit Profile would love to teach you and give you all my knowledge. 415 views in last 30 days 1,377 Lifetime Views 7 Courses 499 Followers Following Expected topics of Current Affairs for SSC/IBPS/UPSC/PCS/UPPSC/ALL OTHER GOVERNMENT EXAMS with some details COLLISION Course Overview A col ision as an isolated event in which two or more colliding bodies exert relatively strong forces on each other for a relatively short time CURRENT AFFAIRS Expected topics of General Awareness for UPSC CSE/SSC/ Railway with some details Collision between particles have been divided broadly into two typer: 1. Elastk collision 1st VOTE enroll By Kumar Ketan By Kumar Ketan By Kumar Ketan (Hindi) Collision for IIT JEE (Hindi) Current Affairs 2018 for UPSC CSE (Hindi) General Awareness: Most Important 50 Question for. https://unacademy.com/user/KumarKetan


  2. In a one dimensional collision between two identical particles A and B, B is stationary and A has momentum p before impact. During impact, B gives impulse J to A (a) The total momentum o the 'A plus B' system is p before and after the impact, and (p -1) during the impact. (b)During the impact A g ves impulse J to B (c)the coefficient of restitutio -1 (d)the coefficient of restitution is L+1


  3. Solution: According to question: Before impact- mui m in After impact- Where J is impulse.


  4. Before impact For partical A, Let, Then momentum = mass velocity mass = m velocity = U1 For partical B, mass=m velocity- 42 Because partical B is stationary


  5. After impact- For partical A, Let, velocity= For partical B, Let, velocity-v2 Then Impulse= F t {F=ma = max t m (axt) 2 2


  6. From law of conservation of linear momentum- where mim2m w2 from eq.2 U2


  7. from eq. (1) then PIeg. (3)


  8. We know that coefficient of restitution- 02-Vi from eq (1), eq (2) and eq (3) JP_J 0-P/m _2J_P 2.J


  9. elastic head on collision with another sphere of heavier mass M at rest collision (no external force acts on system of two spheres ). Statement-2: During a collision of spheres of unequal masses, the heavier (M>>m), then direction of velocity of sphere of mass m is reversed due to exerts more force on lighter mass in comparison to the force which lighter mass exerts on heavier mass.


  10. a)Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1 b) Statement-1 is True, Statement-2 is True; Statement-2 is not a correct explanation for Statement-1 c)Statement-1 is True, Statement-2 is False d) Statement-1 is False, Statement-2 is True