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Basic Numericals based on Collision Part -1 (In Hindi)
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Through this lesson, you can learn how to approach on numericals. In this lesson, I gave you some basic questions which are very important for basics as well as some entrance exams as BHU, HCU, GBTU etc.

## Kumar Ketan is teaching live on Unacademy Plus

Kumar Ketan
#Specialisation in Electronics #6 years teaching experience #Physics Faculty in Kota #"magical education" (211k+ subs) #Writer

U
ma'am May June 2016 ka important nahi Hai Kya pre ke liye???
nice explaination Sir 😍
Arti Bhaira
9 months ago
lgta kya h....real me hi h
1. Kumar Ketan Follow Hey, this is kumar Ketan, I'm graduate in physics and doing further studies. I would love to teach you and give you all my knowledge. 283 Views in last 30 days 1,178 Lifetime Views 5 Courses 460 Followers Following Course Overview Course Overview Expected topics of General Awareness for UPSC CSE SSC / Railway with some details Expected topics of General Science for Railway Group C & D with some details For which diode is used a) Modulation b) Oscillation c) Amplification d) purification VOTE enroll VOTE enroll By Kumar Ketan By Kumar Ketan By Kumar Ketan (Hindi) General Awareness: Most Important 50 Question for... (Hindi) Most Important 100 General Science Questions: Railway... (Hindi) Previous Years Questions asked in UPPSC/SSC 6 Lessons 8 Lessons 25 Lessons https://unacademy.com/user/KumarKetan

2. Problems Of Collision

3. Example 1: lake of ice. He catches a 2-kg football and then moves at 40 cm/s. What was the initial velocity of the football? A 60-kg football player stands on a frictionless A Given: u0; m,2 kg: 60 kg: (2 kg + 60 kg)(0.4 m/s) = (2 kg)2.4 u- 12.4 m/s

4. Example 2: football? How much energy was lost in catching the (2 kg)(12.4 m/s)2 = (62 kg)(0.4 m/s) Loss 154 J = 4.96 J + Loss Loss = 149 J 97% of the energy is lost in the collision!

5. A 2-kg block A and a 1-kg block B are pushed together against a spring and tied with a cord. When the cord breaks, the 1-kg block moves to the right at 8 m/s. What is the velocity of the 2 kg block? The initial velocities are zero, so that the total momentum before release is zero. 0 AVA

6. (1 kg)(8 m/s) (2 kg) YA =-

7. Kumar Ketan Follow Hey, this is kumar Ketan. I'm graduate in physics and doing further studies. I would love to teach you and give you all my knowledge. 283 Views in last 30 days 1,178 Lifetime Views 5 Courses 460 Followers Following Course Overview Course Overview , For which diode is used a) Modulation b) Oscillation c) Amplification d) purification Expected topics of General Expected topics of General Science Awareness for UPSC CSE/SSCfor Railway Group C & D with some Railway with some details details VOTE enroll VOTE enroll By Kumar Ketan By Kumar Ketan By Kumar Ketan (Hindi) General Awareness: Most Important 50 Question for.. (Hindi) Most Important 100 General Science Questions: Railway... (Hindi) Previous Years Questions asked in UPPSC/SSC 6 Lessons 8 Lessons 25 Lessons https://unacademy.com/user/Kumarketan

8. Problems Of Collision 2

9. Example 1 at rest on ice. They move together after the collision at 2.4 m/s. Find the velocity of the skater B before the collision. An 87-kg skater B collides with a 22-kg skater A initially Common speed after Vr= V,-Vc = 2.4 m/s colliding: 2.4 m/s. ul BL B .A BC 87 kg B (87 kg)uB (87 kg + 22 kg)(2.4 m/s) 22 kg (87 kg) -262 kg m/s 11,-3.01 m/s

10. Exampie 2. at rest. The velocity of block afterward is 40 m/s. The bullet passes through the block and emerges with what velocity? A 0.150 kg bullet is fired at 715 m/s into a 2-kg wooden block (0.150 kg)vA (2 kg)(40 m/s) (0.150 kg)(715 m/s) 0.150v(80 m/s) (107 m/s) 0.150v 27.2 m/s) 27.2 m/s 50 VA 181 m/s