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GATE 2015 all thermodynamic questions solutions of morning slot (set 1)
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In this lecture we will see GATE 2015 all thermodynamic questions solutions of morning slot (set 1)

RUTUJA Bothara
Strengthen GATE /PSU/ESE/SSC JE/RRB JE /campus Placements preparation. A passionate mechanical engineer -VIT University

U
Thank you sir
Chetan Gaurav
a month ago
Follow the updated course of this subject... crash course on indian economy Part 1
in last problem lot doubts ….rotation taken in minutes , pressure taken 100,
RUTUJA Bothara
9 months ago
Even if you take p as 105 there will be not much difference in answer and we have to calculate the ans for 1000 rotations for whole system ,the meaning of constant rpm is that its speed
RUTUJA Bothara
9 months ago
The meaning of constant rpm is that its rotational speed is not changing
1. GATE Previous years Thermodynamics questions GATE 2015 Thermodynamics solved questions set 1 By Rutuja Bothara

2. RUTUJA BOTHARA . Perusing B.Tech in Mechanical Engineering from Vellore Institute of Technology, Vellore. (2015-2019) . Cleared JEE Mains 2015 Cleared VITEEE-2015 with AIR 8718 . Cracked HITSEEE-2015 with AIR 91 . Worked as a Career Counsellor in Teachers Academy (2016- 2018) and BOLO app https://unacademy.com/user/rurutujajb96- 9511

3. -For an ideal gas with constant values of specific heats, for calculation of the specific enthalpy. (A) it is sufficient to know only the temperature (B) both temperature and pressure are required to be known (C) both temperature and volume are required to be known (D) both temperature and mass are required to be known

4. it is sufficient to know only the temperature For specific enthalpy mass is not required

5. A Carnot engine (CE-1) works between two temperature reservoirs A and B, where A 900 nd B- 500KA second Carnot engine (CE-2) works between temperature reservoirs Dand C, where 300Kn each cycle of CE-1 and CE-2 all the heat rejected by CE-1to reservoir B is used b CE-2 For one cycle of operation, if the net Q absorbed by CE-1 from reservoir A is 150 MJ, the net heat rejected to reservoir C by CE-2 (in M]) is (a) 10 MJ (b) 35 MJ (c) 45 MJ (d) 50 MJ

6. 72:32. 032 = g3.33 M 2 CE 2 g 2. 93 300 8 3 33 oa SOM

7. Air enters a diesel engine with a density of 1.0 kg/Bi. The compression ratio is 21. At steady state, the air intake is 30 x 10-3kg/s and the net work output is 15 kW. The mean effective pressure (in kPa) is a) 525 KPa b) 250 c) 350 KPa d) 275 KPa

8. Q H 3 Com pressioh Taho V 2 Volcume of ait at inlet in le t Vi V 21 -3 3

9. Mean effective pressure = Work dohu Suwept Vol V1-V2 15 3 (30-428)1 3 S 10 28.57 me

10. Temperature of nitrogen in a vessel of volume 2 m3 is 288 K. A U-tube manometer connected to the vessel shows a reading of 70 cm of mercury (level higher in the end open to atmosphere). The universal gas constant is 8314 J/k mol-K, atmospheric pressure is 1.01325 bar, acceleration due to gravity is 9.81 m/s2 and density of mercury is 13600 kg/3. The mass of nitrogen (in kg) in the vessel is (a) 4.56 kg (b) 5.46 kg (c) 4.34 kg (d) 6.45 kg

11. CA Mol mats 2. 9 PV 194.Gx2 RT m- 0.2.9Gx 288

12. Work done (w) Txo -G28, 318 k mR 0.2X