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Class - 07 (Basic concept builder practice question - 6)
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Class - 07 (Basic concept builder practice question - 6)

Bharat Gupta is teaching live on Unacademy Plus

Bharat Gupta
Engineer by degree Mathematician by Heart. Having 22 years of teaching experience. Visit my youtube channel BHARAT GUPTA-RADIX .

U
Unacademy user
Thank you so much sir for making all d concepts in a clear cut in a lucid manner!!
Doubt- In que.5, why can't we select 1 out of 4 or 2 out of 4.......4 out of 4?
Harish R
10 months ago
I guess those AB & CD are to be considered as just lines , not as four different points
Kamakshi Ahirwar
9 months ago
@Harish, doubt is for this que.- In an election, a voter may vote for any number of candidates not greater than the number to be chosen. There are 7 candidates and 4 members are to be chosen. In how many ways can a person vote? a. 89 b. 98 C. 79 d. 101
Harish R
9 months ago
7+21+35+35 =98
Harish R
9 months ago
7c1+7c2+7c3+7c4
  1. COMBINATION Practical Problem part - 6 Follow Upvote


  2. Problem for this lesson In an election, a voter may vote for any number of candidates not greater than the number to be chosen. There are 7 candidates and 4 members are to be chosen. In how many ways can a person vote? a. 89 b. 98 c. 79 d. 101 A box contains 7 red, 6 blue and 4 black balls. how many selection of three balls can be made so that all three are red balls a. 35 b. 70 . 42 An urn contains 5 different white and 6 different black balls. In how many ways can 6 balls be selected so that there are at least two balls of each colour? a. 425 b. 245 c. 125 d. 625 AB and CD are two parallel lines. On AB there are two point P and Q. On CD there are 8 points. Find number of different triangles which could be formed having 3 of the 10 points as vertices? a. 216 b. 126 c. 64 d. 32


  3. In an election, a voter may vote for any number of candidates not greater than the number to be chosen. There are 7 candidates and 4 members are to be chosen. In how many ways can a person vote? a. 89 b. 98 C. 79 d. 101


  4. In an election, a voter may vote for any number of candidates not greater than the number to be chosen. There are 7 candidates and 4 members are to be chosen. In how many ways can a person vote? a. 89 b. 98 C. 79 d. 101 mt L n L n


  5. In an election, a voter may vote for any number of candidates not greater than the number to be chosen. There are 7 candidates and 4 members are to be chosen. In how many ways can a person vote? a. 89 b. 98 C. 79 d. 101 mauV L n 2


  6. A box contains 7 red, 6 blue and 4 black balls. how many selection of three balls can be made so that all three are red balls a. 35 b. 70 . 42


  7. A box contains 7 red, 6 blue and 4 black balls. how many selection of three balls can be made so that all three are red balls a. 35 b. 70 . 42 34


  8. An urn contains 5 different white and 6 different black balls. In how many ways can 6 balls be selected so that there are at least two balls of each colour? a. 425 b. 245 c. 125 d. 625


  9. An urn contains 5 different white and 6 different black balls. In how many ways can 6 balls be selected so that there are at least two balls of each colour? a. 425 b. 245 c. 125 d. 625 6 b al, with of Lat huo bala. .chulun


  10. An urn contains 5 different white and 6 different black balls. In how many ways can 6 balls be selected so that there are at least two balls of each colour? a. 425 b. 245 c. 125 d. 625 6 b al, with of Lat huo bala. .chulun 2


  11. AB and CD are two parallel lines. On AB there are two point P and Q. On CD there are 8 points. Find number of different triangles which could be formed having 3 of the 10 points as vertices? a. 216 b. 126 c. 64 d. 32


  12. AB and CD are two parallel lines. On AB there are two point P and Q. On CD there are 8 points. Find number of different triangles which could be formed having 3 of the 10 points as vertices? a. 216 b. 126 c. 64 d. 32