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4,20 As per the maximum principal stress theory, when a shaft is subjected to a bending moment Mand torque T. And is the allowable stress in axial tension, then the diameter d of the shaft is given by 3 32 (d) d.no[M+GF.T2] [ESE 1997]

4.28 A shaft of diameter 'd is subjected to bending moment Mand twisting moment T. The developed principal stress will be 16

4,12 A section of a solid circular shaft with diameter D is subjected to bending moment M and torque T The expression for maximum principal stress at the section is 2M T (a) TD D3 16 MM2+ T2 ESE: 1996]

E9VI VALENT REND Na mon ENT G MomeNs

also (m . ) @ Td 3 2 Me- , d 2

4.7 A shaft is subjected to a bending moment Mand a torque T. The equivalent bending moment Meq on the shaft is given by 2 T2 4 4 M+M2 +T2 2 [ESE: 1995]

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Shraddha Bharti

B.tech civil 2017 WBUT || M.Tech environmental 2020 NIT Durgapur || GATE 2017 and 2018 || love teaching, traveling, learning

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Laxman Singh Bhati

2 years ago

thanks brother

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DODDA SRINIVAS

a year ago

at 13:22 in the formula you mentioned M^2....but it is only M plus or minus

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Shraddha Bharti

a year ago

Yess.... Its a mistake.... Its quite obvious that it is M and not M square

DS

DODDA SRINIVAS

a year ago

ok that's fine...it makes us attentive.

DS

DODDA SRINIVAS

a year ago

ok that's fine...it makes us attentive.