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Tangents to a Hyperbola
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In this video, we discuss about the tangents to a hyperbola and their equations.

Sachin Rana is teaching live on Unacademy Plus

Sachin Rana
IVth Year UG, IIT Bombay | YouTuber (143k subs) | Mentored 3 under 100 ranks in JEE Advanced | No. 1 educator for Organic Chemistry.

U
Unacademy user
Last question mein thetha ki value galat hai because you have taken the all slope of of and not sp
I can't believe nobody could make out an obvious error in the end, most probably, nobody tried to solve it by themselves! The slope of SF and not PF is what has been shown in the slide and that is what is required to find the theta!
RN
sir but θ is eccentric angle and must be considered from centre but we took from focus please reply sir
Locus of point p is x^2-y^2+6ax+a^2=0 with constant term a^2 And can be further resolved as aequation of hyperbola (x-3a)^2/8a^2-y^2/8a^2=1
Swaraj
a year ago
Li'l mistake (x+3a)^2 is there in place of (x-3a)^2
  1. 2 2.2 2.


  2. Oiids by- enlo b-3 (m): 4 )4-3 1-0 +- 9


  3. 2. T-0 at 2. - 41 3 41-3


  4. at 2 a- e donne 02 12


  5. The amy erto duaum 1 ehat