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15 lessons,
2h 26m
Locus Problems
833 plays

The very important locus problems are discussing this video with examples.

Sachin Rana is teaching live on Unacademy Plus

Sachin Rana
IVth Year UG, IIT Bombay | YouTuber (143k subs) | Mentored 3 under 100 ranks in JEE Advanced | No. 1 educator for Organic Chemistry.

Unacademy user
Thnx for ur effort will surely help in revision. looking forward to it.
2 nd ques mein y(y-c) =4 kese ho gya?
Regarding the previous the HW solution we could also find the equation of hyperbola using y = mx + a/m
Aman Kumar
a month ago
yes, sir do not tell us about T^2=SS1
Aman Kumar
a month ago
I solve that question by using y =mx+ a/m
Locus of LP is a line parallel to the conjugate axis i.e. the y-axis. Equation is x= asec(theta) which is a line, which itself passes through the assumed point P on the hyperbola.
Sachin Rana
a year ago
Correct. Good.
Mohit Likhar
a year ago
2nd question Mai locus kese aaya please explain to me
As assumed initially.. x1,y1 and x2,y2 are the co-ordinates that lies on the hyperbola.. so we are bringing the value of x1 and y1 in terms of h and k.. now we have x1 and y1 satisfying the equation xy=1 as it lies on it.. therefore we can substitute the values obtained in this equation to obtain the locus by solving further. (i.e. x1=-h-k/2 , y1=-k-8h ).
Mohit Likhar
a year ago
thank you so much
Anytime :-)
Line is parallel to conjugate axis with equation x=asec¥ ( if we consider any point pas (asec¥, btan¥). and point G(0,t) then point L is [(-tab/b^2+a^2) , -t(a^2/b^2+a^2 - 1)] which gives slope of line LP=0
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