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Special Integration Type - 1
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This lesson explains a special type 1 of integral

Vineet Loomba is teaching live on Unacademy Plus

Vineet Loomba
IITian | No. 1 Educator in IIT-JEE | 6 Million Minutes Watch Time | 8+ Years Experience | Youtube: Maths Wallah | vineetloomba.com

U
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Ankita Podder
a year ago
Thank you. Please do rate review and recommend the course.
Pk
Sir please make videos on advance problems and solutions
In case II, if both the m and n are odd natural numbers taab kisko kya put karna hoga ?
this course is something new.
If I am not wrong then my answer of the 1st question is coming....x/4–sin4x/16+sin³2x/24+C...... kyunki 1st step me bahar 1/8 nhi 1/4 aayega na sir???? Can u plz check that......?
Vineet Loomba
a year ago
nhi u r wrong 1/8 ayega ..simple Trigonometry concept ... sin2x and cos2x ke formulas hain
Sidra Hassan
a year ago
No Sir,......jb 4se x aur ÷ krenge toh numerator wala 4 toh totally use hogya ek 2sin²x.cos²x me jo sin²2x aaya aur ek 2cos²x me toh 2cos²x= (1+cos2x) aayega next step me...... aur denominator me 4 hi rh gya na Sir........
Vineet Loomba
a year ago
4sin^2xcos^2x hoga na ki 2 ..apka formula galat hai
Sidra Hassan
a year ago
yaa......okay I get it thank you sir 👍
  1. INDEFINITE INTEGRATION SPECIAL TYPE-1 IIT-IEE MATHS MADE EASY PREPARED BY: ER. VINEET LOOMBA IITiAN | IIT-JEE MENTOR FoR SURE SHoT SUcCESS IN JEE MAIN AND ADVANCED (IIT-JEE)


  2. REVISION COURSE FOR JEE MAIN AND ADVANCED (IIT-JEE) ABOUT ME B.Tech. From IIT Roorkee IIT-JEE Mentor Since 2010 Doubts/Feedback in Comment Section * Comment other topics you want to revise. Follow me @ https://unacademy.com/user/vineetloomba to get updates or search me on Google * Share among your peers as SHARING is CARING!!


  3. FOR 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Integration of type sin"X.cos"xdx Case I If m and n are even natural number then converts higher power into higher angles. Case II If at least m or n is odd natural number then if m is odd put cosx = t and vice-versa. Case III when m + n is a negative even integer then put tan x = t. MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKEE)


  4. FOR 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Example sin X COS X dx Solution. in2x (1cos 2x )dx sin 2x dx + sin2x cos 2x dx 1 sin3 2x 1(1-cos 4x ) dx + = 16 sin 4x sin 2x 16 64 48 MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKee)


  5. FOR 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Example: Solution. put -sinx dx = dt 22 4 (1-t). t. dt -- (t8 -2t6 +t4) dt 7 cos x cos x cos X + c Ans MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKee)


  6. FOR 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) (sinx)1's cosx)7'5 dk j(sin x)1/3(cosx)-7,3dx , a Example 1/3 Solution. | (tan x)1/3 = cos2x X put tanx=t 4 Ans. MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKEE)


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