Sign up now
to enroll in courses, follow best educators, interact with the community and track your progress.
Download
Integration by Parts (Part-1)
4,051 plays

More
This lesson introduces the concept of integration by parts for jee main and advanced

Vineet Loomba is teaching live on Unacademy Plus

Vineet Loomba
IITian | Best Online Maths Educator | Highest Overall Watch Time | 8+ Years Experience | Youtube: Maths Wallah | vineetloomba.com

U
Unacademy user
sir please solve questions with theory
Rishikant Bairwa
2 years ago
okay shweta...i will
sir the problems related to substitution are very tough what should I do?
sir in 2nd example can't we take sin^-1 x as t and then solve it?
Vineet Loomba
3 months ago
After that again u will hv to apply IBP ...why dont u give it a try?
Fry Pan
3 months ago
yes sir I did...it came as integration of sin t. t. dt but after that answer did not match...when I applied ibp... maybe I'll give another try.... thank you for replying Sir, u have a gr8 way of teaching
Vineet Loomba
3 months ago
Ans will match once u convert back t to x which is little bit difficult ..thts why i did by this method
Sir First problem mein - cos2x ki jagah +cos2x aa raha hain....Solution by me : imgur.com/a/sglzz89
Saumit Up
4 months ago
Okay sorry, at 8:10 you explained it as a Typing error
first problem in last step apne cosx ka integration nhi kiya direct answer me 2cosx type krdiya
Vineet Loomba
7 months ago
dhyan se solve kro notebook pe ... cosx ki do baar integration h ... aur bahar 2 hai ..isiliye 2 cos x aya h
User Died
7 months ago
ok ok sir i get it and thnku so much
sir in 1st example why can't we apply integration by parts on the answer that is 2xsinx -x^2cosx they both contains 2 function
Vineet Loomba
a year ago
why do u want do integration again ..answer has already come ...why to apply integration again?
Ankur Kumar
a year ago
sir because the integration has still 2 functions in it . i think that it's not completely integritared
Vineet Loomba
a year ago
Which two functions are there ..its already integrated by integration by parts ...that laat step is the answer
  1. INDEFINITE INTEGRATION INTEGRATION BY PARTS IIT-IEE MATHS MADE EASY PREPARED BY: ER. VINEET LOOMBA IITiAN | IIT-JEE MENTOR FoR SURE SHoT SUcCESS IN JEE MAIN AND ADVANCED (IIT-JEE)


  2. REVISION COURSE FOR JEE MAIN AND ADVANCED (IIT-JEE) ABOUT ME B.Tech. From IIT Roorkee IIT-JEE Mentor Since 2010 Doubts/Feedback in Comment Section * Comment other topics you want to revise. Follow me @ https://unacademy.com/user/vineetloomba to get updates or search me on Google * Share among your peers as SHARING is CARING!!


  3. FOR 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Integration By Parts du dx where u & v are differentiable functions and are commonly designated as first & second function respectively. product of two functions - (first function) x (integral of the second function) Integral of [(differential coefficient of the first function) The integral of the x (integral of the second function)]" MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKEE)


  4. FOR 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) ILATE Rule Choose the first function as the function which comes first in the word ILATE, where; IInverse function, L-Logarithmic function, A-Algebraic function, T-Trigonometric function & E-Exponential function. MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKEE)


  5. FOR 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Illustration: Evaluate:x2 sin x dx Solution: x2 sin x dx = x | sin x dx-1 (2x | sin x dx)dx -x' cos x +2[x scos x dx -ascos x dx)dx =-x-cos x + 2x sin x-2 cos x + c MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKEE)


  6. FOR 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) X sin 'X dx Example Find J Solution Let fint function be sin 'x and second function be a Frst we find the integral of the second f nction,ie. x dr First we find the integral of the second function, i.e. Put t=1-x". Then dt =-2xdx x dx Therefore x sin"xdx = (sin-ix)-1-X2 MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKee)


  7. FOR 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Illustration: Evaluate: (cos#xdx Solution Consider I-cos Vxdx Let then- Vx dx = 2Vxdt Icost.2tdt i.e. or dx = 2t dt SO taking t as first function, then integrate it by part 1-2 | t cos tdt cos tdt dt = 2| tsin t- 1.sin tdt l = 2[tsin t-cost]-c MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKee)


  8. FOR 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Illustration Evaluate : Jit sinx dx x(1-sinx) (1 +sinx)(1 -sin x) dxx sec xdx x sec x tan xdx Solution: Let I= dx dx 1 sin x x(1 sin x) x(1 -sinx) | 1-sin#x coS X x sec xdx - sec xdx dx x secx tan xdx- sec x tan xdx dx tan xdx-xsecx secxdx = [xtan x-enl sec x1]-[xsec x-In l sec x + tan x 1]-c x (tan x - sec x) +secx + tanx)X(1-sin x) -x 1 - sinx) = x ( tan x-sec x) + In + En 1 sin x | +c sec x coS X MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKee)


  9. FOR 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) ENROL for this Course (Free) Enroll 439 Recommend Lessons (Like) E . Rate and Review the Course .Comments . Sharing with friends 15 68 26 ratings 7 reviews Share MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKEE)