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Mole Concept (III)
Sachin bhaiya jo Q4. hai, in that i have calculated option 2 is also correct i calculated that using method of stichiometry.. Can you please check and verify as 1/6(mole of HCL)= 1/3(mole of h2) so, n(HCL) =2 x n( h2) now using n= volume/22.4 we get, Volume(HCL)= 2 x Volume(h2) hence, if Volume of H2 is 3L then according to above relation Volume of HCL is 6L