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Mole Concept (III)
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Sachin Rana is teaching live on Unacademy Plus

Sachin Rana
IIIrd Year UG, IITB | 115/120 in Maths in JEE Main (2016) | Qualified NSEA (Astronomy Olympiad) | YouTuber with over 1,00,000 subscribers.

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(2)
U
Unacademy user
lesson no. 6 ans 88
Shivam Tiwari
a month ago
Can you tell me how?
Ruby mishra
a month ago
x3+1/x3=a3+3a 83+3×8=64+24=88
Shivam Tiwari
a month ago
How you get 83 and 64
Shivam Tiwari
a month ago
(a)^3 = (8)^3 = 512 3a = (3×8) = 24 512+24 = 536
Ruby mishra
a month ago
sir it is 8 ka cube
Shivam Tiwari
a month ago
Yes cube of 8 is 512
Ruby mishra
a month ago
yes sir
Shivam Tiwari
a month ago
Ab aaya 536?
Ruby mishra
a month ago
sir if the sum of first n term of an arithemetic progression is 3n ^2 +2n, then its 10th term is ?
Ruby mishra
a month ago
yes
Ruby mishra
a month ago
ye sum nhi smja
Ruby mishra
a month ago
above one
Shivam Tiwari
a month ago
Iska answer 59 hoga
Ruby mishra
a month ago
kaise
Shivam Tiwari
a month ago
Sn= 3n^2+2n S1 = 3(1)^2+2(1)= 5 S2=3(2)^2+2(2) = 16 a1+a2=16 5+a2=16 a2=11 Ab hume pata h ki an = a+(n-1)×d a10 = 5+(10-1)×6 a10 = 5+54 an = 59
Shivam Tiwari
a month ago
Aaya samjh?
Ruby mishra
a month ago
a1 +a2 kaha se aaya
Shivam Tiwari
a month ago
Hume first term and second term chahiye...to uske liye humne sn me 1 and 2 value put kari
Sachin bhaiya jo Q4. hai, in that i have calculated option 2 is also correct i calculated that using method of stichiometry.. Can you please check and verify as 1/6(mole of HCL)= 1/3(mole of h2) so, n(HCL) =2 x n( h2) now using n= volume/22.4 we get, Volume(HCL)= 2 x Volume(h2) hence, if Volume of H2 is 3L then according to above relation Volume of HCL is 6L
first question ka answer B hai guaranteed.. it remains unchanged..
Aditya Rao
3 months ago
Nope, guaranteed it becomes half