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Mole Concept (III)
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Sachin Rana is teaching live on Unacademy Plus

Sachin Rana
IVth Year UG, IIT Bombay | YouTuber (143k subs) | Mentored 3 under 100 ranks in JEE Advanced | No. 1 educator for Organic Chemistry.

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(2)
U
Unacademy user
Sachin bhaiya jo Q4. hai, in that i have calculated option 2 is also correct i calculated that using method of stichiometry.. Can you please check and verify as 1/6(mole of HCL)= 1/3(mole of h2) so, n(HCL) =2 x n( h2) now using n= volume/22.4 we get, Volume(HCL)= 2 x Volume(h2) hence, if Volume of H2 is 3L then according to above relation Volume of HCL is 6L
first question ka answer B hai guaranteed.. it remains unchanged..
Aditya Rao
a year ago
Nope, guaranteed it becomes half