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Sachin Rana

IIIrd Year UG, IIT Bombay | YouTuber with over 127k subscribers at Sachin Rana [IITB] | Organic Chemistry & Maths Expert.

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Badshah Bilal PS

17 days ago

super classs

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Sarika

6 months ago

x+y=a+b is the answer!

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Arkya ghosh

8 months ago

sir plzz add a video on how to solve questions in which one eq for two lines is given

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Abantika Karmakar

a year ago

The required locus is : x+y = a+b.

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Aditya Singh

a year ago

what is the answer of hw question

Abantika Karmakar

a year ago

I am getting two triangles but I am not sure

Aditya Singh

a year ago

I m getting 4 triangle by solving the equation but when I draw the triangle on axes there is no such triangle are possible

Abantika Karmakar

a year ago

Yes you are right.. as we know it is a right angled triangle therefore we can consider it to be drawn inside a circle with diameter along AB.. therefore two triangles on side ( considering the area) and two on the another side.

Sachin Rana

a year ago

The locus is correct. The homework question has 0 triangles as the answer.

Abantika Karmakar

a year ago

Okay sir.

Aditya Singh

a year ago

thanku abantika

Abantika Karmakar

a year ago

Welcome.. Aditya

Nidhi gupta

10 months ago

can you explain in detail abantika
no. of possible triangle ??????

Nidhi gupta

10 months ago

and eq of locus too
plz

Nidhi gupta

10 months ago

now it got eq of locus but plz tell no. of possible triangle = 0
how??

Abantika Karmakar

10 months ago

I'm really sorry.. I don't have any idea how no triangle is possible.. each time I solve I'm getting some value. If I get to Know the correct explanation I'll surely let you know.

Abantika Karmakar

10 months ago

Ok yeah.. I got it.. consider the point to be (h,k) then find the perpendicular distance of this point from the line opposite it u will get the height and you Know the base as 5 units.. apply 0.5 * 5 * height and equate with area.

Abantika Karmakar

10 months ago

The second equation comes from the condition that sides AC and CB are perpendicular to each other which gives the locus of point C which is a circle. Substitute the value of k from the first equation in this equation and you get the discriminate of the equation to be <0 which gives imaginary value hence no triangle is possible.

Abantika Karmakar

10 months ago

I hope it's clear now ^_^

Rishabh Gangwar

a year ago

Rest solution of Q.1: Putting the values of a' and b' from equation 1 and 2 in equation 3, the locus comes out to be x+y=a+b.

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Vicky Kumar Gupta

a year ago

bhaiya.... in second question how can the sum of distances be 0 , even though modulus also comes with distance formula...... I'm stucked in both of the questions plz help

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