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Bernoulli's Trials | Binomial Distribution
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In this lesson explains the concept of Bernoulli's trials binomial distribution, mean variance, standard deviation

Vineet Loomba is teaching live on Unacademy Plus

Vineet Loomba
IITian | No. 1 Educator in IIT-JEE (Maths) | 2.6 Million Minutes Watch Time | 8+ Years Experience | Youtube: Maths Wallah | vineetloomba.com

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Ma'am u r natural teacher .... Plz make courses on other thinkers 2 as soon as possible.... mains is approaching... anxiety level is high....
sir methods of differentiation
is the theoretical part of this course sufficient for jee advance also?
Vineet Loomba
2 months ago
Yes ..u can match the syllabus if u want for ur satisfaction :)
sir please add more and more questions please please please
in a binomial distribution consisting of 5 independent trials,the probability of 1 and 2 successes are 0.40 and 0.20 respectively.Find P
Good Evening Sir, I have watched the full probability course of yours and it was very helpful. I have one doubt Sir . Q. V Anand and Gary paly a series of 5 chess games. The probability that V Anand wins a game is 2/5 and the probability of Gary winning is 3/5.There is no probability of a draw. The series will be won by the person who wins 3 matches.Find the probability that Anand wins the series (The series end the moment when any of the two win three matches.) Options:- a. 992/3125 b.273/625 c.1021/3125 d.1081/3125 Is there any short way of doing this question?
  1. PROBABILITY FoR SURe SHoT SUcCESS IN JEE MAIN AND ADVANCED (IIT-JEE) JEE MAIN RANK BOOSTER COURSE PREPARED BY ER. VINEET LOOMBA ITIAN IIT-JEE MENTOR


  2. 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) ABOUT ME B.Tech. From IIT Roorkee IIT-JEE Mentor Since 2010. * Doubts/Feedback in Comment Section *Comment other topics you want to revise . Follow me @https://unacademy.com/user/vineet! unacademy omba to get updates * Share among your peers as SHARING is CARING!! Search " vineet loomba unacademy" on GOOGLE


  3. BeRNOULLI'S TRIALS FOR SURE SHOT SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) JEE MAIN RANK BOOSTER COURSE PREPARED BY ER. VINEET LOOMBA ITIAN IIT-JEE MENTOR


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  6. ni a Each exp . (on be divided mfo ture even #5 Auman constant in each tiel Die HolledJo Himes m-H lo Mean = mb


  7. 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Example A pair of dice is thrown 4 times. If getting a total of 9 in a single throw is considered as a success then find the mean and variance of successes 4 36 9 Solution: - probability of getting a total of 9- 36g q=1-9= mean = np = 4 g- p 1 832 variance = npq = 4 x = 81 SUCCESS IN JEE MAIN ER. VINEET LOOMBA (IIT RooRKEE)


  8. 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Example: A pair of dice is thrown 5 times. If getting a doublet is considered as a success, then find the mean and variance of successes Solution In a single throw of a pair of dice, probability of getting a doublet e considering it to be a success, p = 6 mean 5 x 1 5 25 6 6 36 variance 5 x . - SUCCESS IN JEE MAIN ER. VINEET LOOMBA (IIT RooRKEE)


  9. 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Example: Difference between mean and variance of a Binomial variate is '1' and difference between their squares is '11'. Find the probability of getting exactly three success Solution Mean np & variance npq therefore, Also, we know that p + q = 1 Divide equation (ii) by square of (i) and solve, we get, q- 5 1 , p- 6 & n-36 6 1 5 6 Hence probability of 3' success3Cx Ans 6 SUCCESS IN EE MAIN ER. VINEET LOOMBA (IIT RooRKEe)


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