Sign up now
to enroll in courses, follow best educators, interact with the community and track your progress.
Enroll
1k
Previous
Next
✕Download
Bernoulli's Trials | Binomial Distribution
1,151 plays
More
In this lesson explains the concept of Bernoulli's trials binomial distribution, mean variance, standard deviation

Vineet Loomba is teaching live on Unacademy Plus

Vineet Loomba
IITian | No. 1 Educator in IIT-JEE (Maths) | 2.6 Million Minutes Watch Time | 8+ Years Experience | Youtube: Maths Wallah | vineetloomba.com
Unacademy user
Ma'am u r natural teacher .... Plz make courses on other thinkers 2 as soon as possible.... mains is approaching... anxiety level is high....
1
Reply
sir methods of differentiation
0
Reply
is the theoretical part of this course sufficient for jee advance also?
0
Reply
Vineet Loomba
2 months ago
Yes ..u can match the syllabus if u want for ur satisfaction :)
sir please add more and more questions please please please
0
Reply
in a binomial distribution consisting of 5 independent trials,the probability of 1 and 2 successes are 0.40 and 0.20 respectively.Find P
1
Reply
Good Evening Sir, I have watched the full probability course of yours and it was very helpful. I have one doubt Sir . Q. V Anand and Gary paly a series of 5 chess games. The probability that V Anand wins a game is 2/5 and the probability of Gary winning is 3/5.There is no probability of a draw. The series will be won by the person who wins 3 matches.Find the probability that Anand wins the series (The series end the moment when any of the two win three matches.) Options:- a. 992/3125 b.273/625 c.1021/3125 d.1081/3125 Is there any short way of doing this question?
1
Reply

  1. PROBABILITY FoR SURe SHoT SUcCESS IN JEE MAIN AND ADVANCED (IIT-JEE) JEE MAIN RANK BOOSTER COURSE PREPARED BY ER. VINEET LOOMBA ITIAN IIT-JEE MENTOR


  2. 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) ABOUT ME B.Tech. From IIT Roorkee IIT-JEE Mentor Since 2010. * Doubts/Feedback in Comment Section *Comment other topics you want to revise . Follow me @https://unacademy.com/user/vineet! unacademy omba to get updates * Share among your peers as SHARING is CARING!! Search " vineet loomba unacademy" on GOOGLE


  3. BeRNOULLI'S TRIALS FOR SURE SHOT SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) JEE MAIN RANK BOOSTER COURSE PREPARED BY ER. VINEET LOOMBA ITIAN IIT-JEE MENTOR


  4. 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Follow me on Unacademy for Next live Special Class Strategy for JEE Main and Advanced V Limits, Continuity, Differentiability v Sets, Relations and Functions Indefinite Integration Trigonometry V Definite Integratiorn VApplications of Derivatives Complex Number Permutations Combinations Binomial Theorem V Logarithmic Functions V Sequences Series V Straight Lines Applications of Integrals Circles (Detailed Course) Probability Most Important Questions in IIT-IEE Mathematics Parabola (Detailed Course) Ellipse (Detailed Course) V Inverse Trigonometry Upcoming Courses next month: Mathematical Reasoning Coordinate Geometry Differential Equations


  5. 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) SPECIAL ANNOUNCEMENT Share useful links and advice with your learners... CRASH COURSE FOR JEE MAIN 2019 (JANUARY SESSION) Find courses & lessons 735 Courses IIT JEE 2,521 Courses Str Chemistry 797 Courses Details in Plus Tab wwEest HINDI Home My Library Plus Profile SUCCESS IN JEE MAIN ER. VINEET LoOMBA (IIT RooRKEE)


  6. ni a Each exp . (on be divided mfo ture even #5 Auman constant in each tiel Die HolledJo Himes m-H lo Mean = mb


  7. 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Example A pair of dice is thrown 4 times. If getting a total of 9 in a single throw is considered as a success then find the mean and variance of successes 4 36 9 Solution: - probability of getting a total of 9- 36g q=1-9= mean = np = 4 g- p 1 832 variance = npq = 4 x = 81 SUCCESS IN JEE MAIN ER. VINEET LOOMBA (IIT RooRKEE)


  8. 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Example: A pair of dice is thrown 5 times. If getting a doublet is considered as a success, then find the mean and variance of successes Solution In a single throw of a pair of dice, probability of getting a doublet e considering it to be a success, p = 6 mean 5 x 1 5 25 6 6 36 variance 5 x . - SUCCESS IN JEE MAIN ER. VINEET LOOMBA (IIT RooRKEE)


  9. 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Example: Difference between mean and variance of a Binomial variate is '1' and difference between their squares is '11'. Find the probability of getting exactly three success Solution Mean np & variance npq therefore, Also, we know that p + q = 1 Divide equation (ii) by square of (i) and solve, we get, q- 5 1 , p- 6 & n-36 6 1 5 6 Hence probability of 3' success3Cx Ans 6 SUCCESS IN EE MAIN ER. VINEET LOOMBA (IIT RooRKEe)


  10. 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) ENROL for this Course (Free) Enroll 439 Recommend Lessons (Like) E Rate and Review the Course .Comments . Sharing with friends 15 1. 68 111 ratings 21 reviews Share SUCCESS IN JEE MAIN ER. VINEET LOOMBA (IIT RooRKEE)