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CBSE Class 11 » CBSE Class 11 Study Materials » Mathematics » Miscellaneous Examples
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Miscellaneous Examples

In this article, we will look at various miscellaneous examples in mathematics. Miscellaneous exercises help prepare for competitive tests.

Table of Content
  •  

NCERT solutions for class 11 Maths Miscellaneous Exercise have five questions crafted to push a student to his limits. These are complex sums and require kids to devote their complete concentration. These problems aim to test the foundational understanding of a child’s concepts. Additionally, it teaches kids how to apply the fundamental theories to higher-level sums.

Miscellaneous Examples

1. From the walking sets, select a set that is a subset of one and the other: 

A = {x: x ∈ R and x satisfy x2 8x + 12 = 0} 

B = {2, 4, 6}

C = {2, 4, 6, 8…}

D = { 6}

A = {x: x ∈ R, where x satisfies x2 8x + 12 = 0} 

2 and 6 are the basics of x28 x + 12 = 0, as shown in response to the request. 

Approach:

A = {2, 6} 

B = {2, 4, 6}

C = {2, 4, 6, 8…}

D = {6}  

SoD ⊂ A ⊂ B ⊂ C

SoA ⊂ B, A ⊂ C, B⊂C, D⊂A, D⊂B, D⊂C

2. Determine if the attestation is legitimate or deceiving. If it is legitimate, show it. If it is counterfeit, give a model: 

  1. If x ∈ An and A ∈ B, then x ∈ B 

  2. If A ⊂ B and B ∈ C, then, A ∈ C 

  3. If A ⊂ B and B ⊂ C, then, A ⊂ C 

  4. If A ⊄ B and B ⊄ C, then, A ⊄ C 

  5. If x ∈ An and A ⊄ B, then x ∈ B 

  6. If A ⊂ B and x ∉ B, then, x ∉ A 

Solution:

  1. False 

Let: 

A = {1, 2} and B = {1, {1, 2}, {3}} 

We have: 

2 ∈ {1, 2} and {1, 2} ∈ {1, {1, 2}, {3}} 

Consequently, we get: 

A ∈ B 

We know: 

{2} ∉ {1, {1, 2}, {3}} 

  1. False 

Let: 

A {2} 

B = {0, 2} 

Besides: 

C = {1, {0, 2}, 3} 

From the request: 

A ⊂ B 

Along these lines: 

B ∈ C 

We know: 

A ∉ C 

  1. True 

Let: 

A ⊂ B and B ⊂ C 

If: 

x ∈ A 

Then, we have: 

x ∈ B 

Besides: 

x ∈ C 

Thus: 

A ⊂ C 

  1. False 

Let: 

A ⊄ B 

As well: 

B ⊄ C 

If:

A = {1, 2} 

B = {0, 6, 8} 

Besides: 

C = {0, 1, 2, 6, 9} 

∴ A ⊂ C 

  1. False 

Let: 

x ∈ A 

Also: 

A ⊄ B 

If:

A = {3, 5, 7} 

As well: 

B = {3, 4, 6} 

We know that: 

A ⊄ B 

∴ 5 ∉ B 

  1. True 

Let: 

A ⊂ B 

Also: 

x ∉ B 

If:

x ∈ A, 

We have: 

x ∈ B 

From the request: 

We have x ∉ B 

∴ x ∉ A

3) How many words can be formed by using all the word ‘equation’ letters so that the vowels and consonants are displayed together?

The word ‘equation’ has five vowels, A, E, I, O, and U, and three consonants, Q, T, and N. Each vowel and consonant must occur simultaneously, so they are accepted as separate items (AEIOU) and (QTN). Then, the stages at these two points run at the same time. This number is ²P, ² = 2! Five related to each of these stages and five vowel levels are taken at once. The orders of all three consonants are acquired at the same time. Then, by increasing the standard, the required number of words is = 2! x 51 x 3! = 1440.

4) From the letters of the word ‘daughter’, how many words can each of the two vowels and the three consonants form?

The word ‘daughter’ has exactly three vowels, A, U, and E. Five consonants, D, G, H, T, and R. The number of approaches to select two vowels from 3 vowels is = ³ C₂ = 3 2. The number of approaches to select three consonants from 5 consonants is = $ C₁ = 10. Therefore, the number of mixed two vowels and three consonants is = 3 × 10 = 30. You can set these 30 mixes of 3 vowels and three consonants at 5. Therefore, the number of different words needed is = 30 x 5! = 3600. 

5) If the different permutations of all the letters of the word EXAMINATION are listed in a dictionary, how many words are there in this list before the first word starting with E? 

Given the word, ‘examination’ has 11 letters, of which A, I, and N appear twice, and various other letters appear only once. The words that will be recorded before the words beginning with the letter E in a list will be those beginning with An. To get the number of words beginning with A, the letter An is fixed at the super left position, after which the other ten letters are taken all at once.  Since there are 2 Is and 2 Ns in the remaining ten letters, 10! Several words beginning with A = = 907200 2!2! 

Along these lines, the expected quantities of words are 907200.

Conclusion 

The inquiries in various activities are significant, according to the assessment perspective. They have been asked in numerous past tests, so doing those is likewise significant. We have also included some miscellaneous concepts and miscellaneous properties in FAQs for better understanding and revising of the concepts well before exams.

 
faq

Frequently asked questions

Get answers to the most common queries related to the CBSE Class 11 Examination Preparation.

What are some miscellaneous concepts?

Ans : A positive integer is ...Read full

Review some miscellaneous properties?

Ans : First, one intro...Read full

Are various activities significant for class 12 maths?

Ans : Indeed, it is generally significant in contrast with working out.   ...Read full

Are various inquiries significant?

Ans : Indeed the inquiries in different activities are significant according to the assessment pers...Read full

What is the different activity?

Ans : The random activity contains additional inquiries covering the whole subject in the section. ...Read full

Ans :

  1. A positive integer is prime if it has exactly two factors.
  2. A group is a set together with an associative binary operation such that there is an identity element, and every element has an inverse.
  3. Let X be a metric space. A subset Y of X is open if, for every y in Y, there exists d> 0 such that x is in Y for every x with d(x,y)< d.
  4. A function f:X→ Y is an injection if no element of Y has more than one preimage. That is, f(x)=f(y) ⇒ x=y.
  5. Let A be a set of positive integers, and for each n let dn=n-1|A intersect {1,2,…,n}|. That is, dn is the proportion of numbers up to n that belong to A. When dn approaches a limit d as n approaches infinity, A is said to have density d. The upper density of A is defined as the lim sup of the dn.
  6. For html reasons write E for the empty set. Then the number 4 is the set {E,{E},{E,{E}},{E,{E},{E,{E}}}}.
  7. Let x and y be mathematical objects. The ordered pair (x,y) is the set {x,{x,y}}.
  8. A real number is a partition of the rational numbers into two sets A and B where each element of A is smaller than each element of B.
  9. A function from A to B is a subset F of the Cartesian product AxB with the property that for every a in A there is exactly one b in B such that (a,b) is in F.
  10. The function f(x)=sin(x) is the function f:R–> R defined by f(x)=x-x3/3!+x5/5!-… .

Ans :

  • First, one introduces Euclid’s algorithm and shows that it leads to the following statement: for any two integers, x and y, there exist integers h and k such that hx+ky=(x,y), where (x,y) is the highest common factor of x and y.
  •  Next, one deduces from this the result that if p is a prime and p divides ab then p divides a or p divides b. (Proof: if p does not divide a, then (p,a)=1, so by the previous result, we can find h and k such that hp+ka=1. Then hpb+kab=b. Since p divides ab and p obviously divides hpb, we deduce that p divides b.)
  • Then, one deduces from this, by an easy inductive argument, that if p divides a1…ak then p divides ai for some i.
  •  Lastly, one takes a supposed minimal counterexample to the theorem. So let p1…pr=q1…qs, where the pi and qj are all primes and not the same ones up to a reordering. By minimality, no pi is equal to any qj (or we could divide through and get a smaller example). But p1 divides the product of the pi and hence the product of the qj. By Step 3, p1 divides some qj, which is nonsense as qj is a prime not equal to p1.

Ans : Indeed, it is generally significant in contrast with working out.

 

 

Ans : Indeed the inquiries in different activities are significant according to the assessment perspective. They have been asked in numerous past tests, so doing those is additionally significant.

Ans : The random activity contains additional inquiries covering the whole subject in the section. The last exercise of NCERT Solutions for Class 11 Maths Chapter 2-Relations And Functions depends on every one of the subjects in part, as per the following: Cartesian Product of Sets.

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Download NEET 2022 question paper
.

Trending Topics

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  • PPT Full Form
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combat_iitjee

Important Links

  • NCERT Solutions
  • NCERT Books
  • Physics Formulas
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testseries_iitjee
Download NEET 2022 question paper
.
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