(Hindi) Arithmetic: Time and Work with Pipes and Cistern

1) Using (A+B) and (B+C) find out their respective efficiency and total work, Total Work=60 units; (A+B)=2 units per day; (B+C)=3 units per day 2) A work for 5 days and B work for 15 days, break B's work into 5+10 days. When A individually works for 5 days and then B work for next 5 days = A+B working for 5 days= A+B's Efficiency*2= 10units. 3) B work for remaninig 10 days, break C's 18 days work into 10+8 days; Just like step 2, B+C 10 day work = 3*10=30 units 4) Remainig work=60 - (30+10)= 20 which is done by C alone in 8 days, therefore C's efficiency = (20/8)= 5/2 5) If C alone had to do all the work= total work/ C's efficiency = 24 Days

for full work 72*15(36*15=half,,) Now remaining work is Half. which is equal to 9*No of mens

Work1 = Work2 = 1/2(Half); dono side 1/2 cancel ho jayega; MDHEW wale formula mein daal kar dekh

M+B = 24 Then total work by them. (M+B) *24 Now. M works for 6 days. Then M+B will be working for 20 days. Total work by them. 6M + (M+B)20 Equate both the total work. As they are equal works. (M+B) 24 = 6M + (M+B)20 Solving. We get. 1M = 2B Efficiency ratio wud be. M :B = 2:1 Put in any equation. Total work will be. (2+1)24 = 72 Now. Time taken by boy. Total work / B’s efficiency. = 72/1 72 days.

SS

galat ho bhai. Dono pronunciation sahi hai. Ek American hai eK british.