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Straight Lines Important Questions Set-2 (Solved)
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This lesson takes up problems on straight lines

Vineet Loomba is teaching live on Unacademy Plus

Vineet Loomba
IITian | No. 1 Educator in IIT-JEE (Maths) | 2.6 Million Minutes Watch Time | 8+ Years Experience | Youtube: Maths Wallah |

Unacademy user
sir please upload more problems
best approach to solving the problem.... And bhaiya plzz uplode more and more problem practice as a medicene for jee January
Vineet Loomba
5 months ago
Okay sure ..dont forget to rate the course 5 stars
And also uplode some taugh problems as faster as possible...
Vineet Loomba
5 months ago
Did you find these easy ?
Dhurandhar Kumar
5 months ago

  2. FOR 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) ABOUT ME B.Tech. From IIT Roorkee -$ IIT-JEE Mentor Since 2010. Youtube Channel with 10k Active Followers & Founder @ * Follow me @ to get unacademy updates or search me on Google * Share among your peers as SHARING is CARING!!

  3. FOR 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Other Detailed Courses Made so far on Unacademv: V Strategy for JEE Main and Advanced V Sets, Relations and Functions V Trigonometry V Applications of Derivatives Limits, Continuity. Differentiability V Indefinite Integration Definite Integration Complex Number V Logarithmic Functions V Sequences Series V Most Important Questions in IIT-JEE Permutations Combinations Binomial Theorem V Straight Lines V Applications of Integrals MathematicS V Parabola (Detailed Course) v Inverse Trigonometry V Mathematical Reasoning V Ellipse (Detailed Course) V Hyperbola V Differential Equations Circles (Detailed Course) V Probability Upcoming Courses next month: Coordinate Geometry > Differential Equations ER. VINEET LOOMBA (IIT RooRKee) MATHEMATICS FOR IIT-I

  4. 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Given - and ax by 1 are two variable lines, 'a' and 'b' being the parameters connected by the relation ab2 ab The locus of the point of intersection has the equation (A") x2 + y2 + xy-1-0 (C) x2 + y2 + xy + 1-0 Ex (B) x2 + y2-xy + 1-0 (D) x2 + y2- -1-0 [So et (h, k) be point of intersection then given a +b-ab ah kb1 multiply h2+k2+hk(0+4)-1 SUCCESS IN EE MAIN 2019 ER. VINEET LOOMBA (IIT RooRKEe)

  5. 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Ex. A ray of light passing through the point A(1, 2) is reflected at a point B on the x - axis and then passes through (5, 3). Then the equation of AB is (A*) 5x + 4y 13 (C) 4x + 5y 14 (B) 5x - 4y-3 (D) 4x - 5y6 13 N (5, 3) Hint A(1, 2 (a, 0) SUCCESS IN EE MAIN 2019 ER. VINEET LOOMBA (IIT RooRKEe)

  6. 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) -0, where 2 + -2, If the lines x + y + 1-0 ; 4x + 3y + 4-0 and x + y are concurrent then (A) -1, --1 Ex. (B) -1,p- 1 [Sol. Lines are x+y+1-0; 4x +3y +4-0 and x + y+ 0, where 2+p2-2 4 3 4 0 SUCCESS IN JEE MAIN 2019 ER. VINEET LOOMBA (IIT RooRKEE)

  7. 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) The distance between the two parallel lines is 1 unit. A point 'As chosen to lie between the lines at a distance 'd' from one of them. Triangle ABC is equilateral with B on one line and C on the other parallel line. The length of the side of the equilateral triangle is Ex 2 d--d+1 3 (A) Vd +d+1 x cos (e+ 3 0 ) = d--(1) and x sin = 1-d-(2) dividing V3 cot = (B*) 2 (C) 21d2-d+1 [ Hint: (1- d) , squaring equation (2) and putting d2 -d +1 the value of cot , x2 (4d2-4d+ 4) x = 2 SUCCESS IN EE MAIN 2019 ER. VINEET LOOMBA (IIT RooRKEe)

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