## Kumar Ketan is teaching live on Unacademy Plus

unacademy 62.9k views 4.8 Kumar Ketan Follow me on the Unacademy #15 Educator in IIT JEE #6 years teaching experience #IIT JEE Physics #YouTuber 'magical education" (170k+ subs) #Unacademy educator (60k+ lifetin eviews) 3k 2 37 Followers Following Courses Get updates about new courses . Watch all my lessons . Download slides and watch offline Message Lists (1) Kumar Ketan HINDI IT JEE Physics by Kumar Ketan for IT JEE 52 saves Kumar Ketan

In the circuit shown in figure, the current gain, 100 for the transistor. What would be the base resistance so that VCE = 5 V? (Neglect VSE) 10 VVcc E VCE BE IE (a) 2x 103 (c) 1 106 (b) 2>< 105 (d) 500

Here, = 100, VCE = 5 V, VCC-10 V =1C or ID=le =le As 100 Also, VCE Vcc IcRL or 5V= 10 V-Ic 1000 5 V =5 10-3 A .. c 1000

and IR =5 10-3A =5 10-5 A (Using (i) 100 Thus, RgCCBE 10 V =2x 10"(2 (neglecting VBE) 5 10", A

An oil drop of n excess electrons is held stationary under a constant electric field E in Millikan's oil drop experiment. The density of oil is p. The radius of the drop is 11/2 3neE 2neE (d) 3nps (a) 3nelE (c) l-one 4T0Pg 4TteE

Let r be radius of the drop. Then the mass of the drop is 4 -volume x density tr3 Since the drop has n excesselectrons therefore it is negatively charged and the charge E on the drop is 3 n excess electrons qE mg

As the drop is held stationary under the constant electric field E, .. weight of the drop force on the drop due to electric field mg qE 4 1/3 3 4TPg

Displacement method is applicable to determine the focal length of convex lens. In this method, the applicable formula is 2 2 4 D Object Screen

Here, D distance between object plane and screen on which image is formed, f focal length of lens, x distance between two position of lens. To determine focal length of lens, the measure values of D and x are 90.0 cm and

D2 -x2 4 D Inf- In(D2- x2) - In(4D) I d or 4D dy 1 df or or 2 90.0 0.1 7200 2 30 0.1 0.1 7200 90 -4 10-190 n=4

In the circuit shown in figure, the current gain, 100 for the transistor. What would be the base resistance so that VCE = 5 V? (Neglect VSE) 10 VVcc E VCE BE IE (a) 2x 103 (c) 1 106 (b) 2>< 105 (d) 500

and IR =5 10-3A =5 10-5 A (Using (i) 100 Thus, RgCCBE 10 V =2x 10"(2 (neglecting VBE) 5 10", A

An oil drop of n excess electrons is held stationary under a constant electric field E in Millikan's oil drop experiment. The density of oil is p. The radius of the drop is 11/2 3neE 2neE (d) 3nps (a) 3nelE (c) l-one 4T0Pg 4TteE

Let r be radius of the drop. Then the mass of the drop is 4 -volume x density tr3 Since the drop has n excesselectrons therefore it is negatively charged and the charge E on the drop is 3 n excess electrons qE mg

FIVE-STAR RATING! RECOMMENDED Unacademy.com/user/kumarketan ENROLL UPVOTE

unacademy 62.9k views 4.8 Kumar Ketan Follow me on the Unacademy #15 Educator in IIT JEE #6 years teaching experience #IIT JEE Physics #YouTuber 'magical education" (170k+ subs) #Unacademy educator (60k+ lifetin eviews) 3k 2 37 Followers Following Courses Get updates about new courses . Watch all my lessons . Download slides and watch offline Message Lists (1) Kumar Ketan HINDI IT JEE Physics by Kumar Ketan for IT JEE 52 saves Kumar Ketan

In the circuit shown in figure, the current gain, 100 for the transistor. What would be the base resistance so that VCE = 5 V? (Neglect VSE) 10 VVcc E VCE BE IE (a) 2x 103 (c) 1 106 (b) 2>< 105 (d) 500

Let r be radius of the drop. Then the mass of the drop is 4 -volume x density tr3 Since the drop has n excesselectrons therefore it is negatively charged and the charge E on the drop is 3 n excess electrons qE mg

Here, D distance between object plane and screen on which image is formed, f focal length of lens, x distance between two position of lens. To determine focal length of lens, the measure values of D and x are 90.0 cm and

FIVE-STAR RATING! RECOMMENDED Unacademy.com/user/kumarketan ENROLL UPVOTE