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PYQs on Basic Networks (Q.80)
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In this lesson I've discussed PYQs based on basic networks.

## Pawan Chandani is teaching live on Unacademy Plus

Pawan Chandani
Faculty of GATE/ESE (Electrical Engineering) , Also a YouTuber and teaches Electrical Eng. subjects on YouTube | Jony Ive Award Winner

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highly helpful course thank you sir
1. PYQs on Basic Networks - Pawan Chandani

2. 11:01 AM Saved Preparation Strategy for Electrical & Electronics Measurements O saved Wy-Pavn Chandan ib 128 likes 16 comments Share Edit Review HINDI Basics of Measurements (Hindi) Part 1: Electrical and Electronic Measurements your Pawan Chandani Follow 8.2k Followers 4.7 (260 ratings) Write a review Done Preparation Strategy for Electrical And 01 Electronics Measurements Playing Basics of Measurements (in Hindi) 11:23 02 Error Analysis Part 1 (in Hindi) 03

3. 0.80 A bar of Iron 1cm2 in cross section has 10-4 wb of magnetic flux in it. If H,- 2000, what is the magnetic field intensity in the bar? a) 398 x 10-4 At/m b) 398 At/m c) 398 x 104 At/m d) 796 x 103 At/m [SSC JE 2015]

4. Q.80 A bar of Iron 1cm2 in cross section has 10-4 wb of magnetic flux in it. If = 2000, what is the magnetic field intensity in the bar? a) 398 x 10-4 At/m b) 398 At/m c) 398 x 104 At/m d) 796 x 103 At/m [SSC JE 2015] 01 -- 1o-Y 2 iven 2000 8 1 = 337.8 Atlm

5. Q. 81 A current of 2 A passes through a coil of 350 turn wound on a ring of mean diameter 12 cm. The flux density established in the ring is 1.4 wb/m2. Find the value of relative permeability of iron. a) 600 b) 210 x 10 c) 1200 d) 191 [SSC JE- 2015]

6. Q. 81 A current of 2 A passes through a coil of 350 turn wound on a ring of mean diameter 12 cm. The flux density established in the ring is 1.4 wb/m2. Find the value of relative permeability of iron. a) 600 b) 210 x 103 c) 1200 d) 191 [SSC JE 2015] N 350 ven 0

7. Q. 81 A current of 2 A passes through a coil of 350 turn wound on a ring of mean diameter 12 cm. The flux density established in the ring is 1.4 wb/m2. Find the value of relative permeability of iron. a) 600 b) 210 x 103 c) 1200 d) 191 [SSC JE 2015] N 350 ven mean leng H

8. Mean diameler- 2 cm ean radius 6 cm) mean lenjk Mean length; 2 6x10-m mean radius 350X 2

9. Mean diameler- 2 cm ean radius 6 cm) mean lenjk Mean length; 2 6x10-m mean radius H-Ni 350X 2 8 toos -600

10. Q.82 Find the node voltage VA a) 5.66 V b) 6 V c) 6.66 V d) 5 V [SSC JE 2015] 1 12 U 123 R 2 8

11. Q.82 Find the node voltage VA a) 5.66 V b) 6 V c) 6.66 V d) 5 V [SSC JE 2015] abbly ing KCL at node n A 12 1 39-18-0 /8/

12. Q. 84 A node in a circuit is defined as a: a) Junction of two or more elements b) Closes path c) Group of interconnected elements d) Open terminal of an element [SSC JE 2015]

13. Q. 85 When a source is delivering maximum power to the load, the efficiency will be a) Below 50 % b) Maximum c) 50 % d) Above 50 % ISSC JE 2015] MPT

14. Q. 87 During the resistance welding, the heat produced at the point is proportional to a) PR b) Current c) Volt-Ampere d) Voltage [SSC JE 2015]

15. Q. 87 During the resistance welding, the heat produced at the point is proportional to a) PR b) Current c) Volt-Ampere d) Voltage [SSC JE 2015] Heat = 12 Rit eat R ()

16. Q. 89. The current 'I' in the circuit shown below is a) 1A b) 1.7 A c) 2.7 A d) 3.7 A [SSC JE - 2015] 1A 2A 80 1.3A MA 3 A 2A n8