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8 lessons,
1h 5m
Preparation of Alkynes
8,400 plays

We discuss the use of Alc KOH and NaNH2. Let us see that how can alkynes be prepared from them and later on, the formation of salts.

Sachin Rana is teaching live on Unacademy Plus

Sachin Rana
IVth Year UG, IIT Bombay | YouTuber (143k subs) | Mentored 3 under 100 ranks in JEE Advanced | No. 1 educator for Organic Chemistry

Unacademy user
Really very nice introduction of course!
Navneet Kaur
2 years ago
sir in 3rd slide why didn't NH2- attacked CH3
plz explain the reaction mechanism of boiling with alc KOH and NaNH2/ paraffin.
In the second slide, you just mentioned that we have taken NaNH2 for the formation of product (B) because alc. KOH is a weaker base than NaNH2. I was wondering that can we replace alc. KOH with NaNH2 in the first step (formation of (A)) since NaNH2 is stronger base than alc. KOH and can easily conduct the reaction, or are there some other limitations?
Guru Vishnu M
a year ago
Have the same doubt sir. Kindly reply Sachin Sir.
Nidhi Jha
a year ago
yes,there is a second method to obtain alkenyl halide from vicinal and geminal dihalides by treatment with strong base sodamide or NaNH2 ,it will undergo E2 elimination and for forming alkyne again treat it with same equivalent of might be possible that that NH2 being hindered base would not yield product.
a year ago
NaNH2 is a s.b as well as a strong if we take it in 1st case substitution products may also occur.while in 2nd case substitution doesnot occur as L.G is present over sp2 hybridised carbon
How koh react with terminal alyne to produce non terminal alkyne
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