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Expected Chemistry Questions: Part 1
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Sachin Rana is teaching live on Unacademy Plus

Sachin Rana
IVth Year UG, IIT Bombay | YouTuber (143k subs) | Mentored 3 under 100 ranks in JEE Advanced | No. 1 educator for Organic Chemistry

Comments
(18)
U
Unacademy user
awesome course thank u sir
sir in Question no. 7 , ammonia is a strong ligand so all electrons will make pair therefore it should be diamagnetic 🤔🤔 and 2nd option will also be correct.......sir please see this ....if I am wrong somewhere then rectify me🙏🙏
AS
Aviprit Shah
5 months ago
same question from my side🤔
Deepak Verma
5 months ago
yes Aviprit
Arjun Hurket
5 months ago
In +3 Oxidation state H20 acts as strong field ligand with an exception of Fe+3
Deepak Verma
5 months ago
yeah......for Co+3 and Cu+2 oxygen donating ligands act as SFL.....it was new information for me😂 but it's helpful......
Sir in question 7, why is [Co(h20)6]3+ not paramagnetic? H20 being a weak field ligand won't promote pairing right?
Sachin Rana
5 months ago
It is an exception where H2O behaves as a SFL
Kabir Singh
5 months ago
??? exception sir please, its not time for kota factory. there is nothing called exception in science everything must have a reason as my chemistry teacher always said.
Sir in question 9 why doesn't ring expansion takes place it should form a 6 membered ring?
AS
Ahbar Siddiqui
5 months ago
because the the carbocation will have to shift to the other carbon and there is no reason for carbocation to move in the first place because it is already at tertiary carbon, if the carbocation had been on methyl carbon which is outside the ring then ring expansion would have taken place.
Sachin Rana
5 months ago
Yes, correct Ahbar
Sia Sharma
5 months ago
ohh okay thank you Ahbar
Bhaiya, in the question 7 why can't we chose the option B as an answer????. Please reply. And, if it is an exception then can you please suggest something from where I can read these types of exceptions in inorganic....
Lakshay Parashar
5 months ago
Bhaiya ji, in the next question i.e., the 8th one. Why the KCN can't substitute the OH present in the compound ( via SN2 mechanism)???
NS
Sir in Q.7 option C NH3 is a strong field ligand so it will not form inner orbital complex.
Sachin Rana
5 months ago
It is an exception where H2O behaves as a SFL
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