Sign up now
to enroll in courses, follow best educators, interact with the community and track your progress.
Download
Diodes & BJT Part 6 (in Hindi)
74 plays

More
Mcqs on BJT and diodes are discussed in detail.

Ravendra Yadav is teaching live on Unacademy Plus

Ravendra Yadav
Am an engineer, a YouTube channel name ESE THRILLER and have more than 2 years of teaching experience for ESE/GATE🙂

U
Unacademy user
Very well explained 😊
At saturation output of transister is shorted (almost), both the junction FB .. Vce=0 almost.. hence collector voltage almost equal emitter voltage
Ravendra Yadav
9 months ago
Correct but during question solving we take Vce= 0.2
Mriganka Mukherjee
9 months ago
Yes. that is the value available in data sheet of common BJT..
  1. Final Practice Session for IES 2019 Topic: Time Response Analysis By Ravendra Yadav


  2. HELLO! I am a BE Graduate in Electrical Engineering. Currently am pursuing M.Tech in Govt. engineering college jabalpur. And also a UPSC ESE aspirant. Qualified GATE in 2016 & 2017 Has one year experience in online teaching meb63 Ravendra Yadav


  3. ostor ekaugu 0,5% from its nominal value. o.g the (b) 5% 757- 2.5 Solution 5


  4. (9) (b) he collector poten tial ewitter potontiol is more than base clr potenHal e than bage emi rter poten tial mor emitter Colle cher polen tial ot at Same pot en ti more tl) t boe eutler couesas almott at same pot en tial A BJT has Common Bal egar 0.99 . Common en JTTer wil be (b) 99 CC) o Soution- Common Bare Gain ( ): 0.99 Common cuwTler G1ai


  5. ) Coleel Base Solution- heolowu slaliment i not carect? approx. deubles in a eratyre


  6. () Reverge Satusatien cusse silicon diod e thal umani u diade C) The u votae sili con diode s G ermQni 0.9 n tho c mode. The culiet Qi CC mode - b) 99 (C) 1.01 (d) 0- 9 9. Solu Hon- 1-0, 9 99 cuuuut gaiu


  7. Ravendra yadav Follow Am an engineering graduate and upsc engineering services aspirant. Have any doubt?? don't worry I will hunt ito RATE REVIEWw RECOMMEND Please follow me and Share my courses Thank you!