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Chemical Equilibrium: Part-5 : Numericals- NEET , JEE
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This video explains "How to solve Numericals of Chemical Equilibrium"

Educator | Chemistry | NEET | JEE Teaching students for Cracking NEET , IIT-JEE , AIIMS , XII & XI since 1998.

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In Web Buckling. It is the case of low shear, Then, is there any need of this long calculation.?
1. Chemical Equilibrium art- 5

2. Chemical Equilibrium art- 5

3. Chemical Equilibrium art- 5

4. Writing the expression for Equilibrium Constant [Product] Reactant ja Active mass of Solid & Pure liquid in excess is one Pure Liquid in excess]1 [Solid ]- 1

5. 2 (s) 2Hl(ag) 2 (aq) + 2 (aq K= [Hlaa) ? We Know [ Solid ] 1 [ 12 (s)11

6. 2Hl(ag) 2 (aq) + (aq) We Know Solid 1:1 12 (s) ] = 1 Hlag) 12 [ H2 (aa) Kc

7. 2Hl(ag) 2 (aq) + (aq) e KnoW 12 (s) ] = 1 Hlag) 12 [ H2 (aa) | Units = mol It

8. Write Expression for equilibrium constant for following reaction? CaCO3 (s) CaO(s) + CO2 (g) (Caol ICO2 (el [CaCOs sl

9. Write Expression for equilibrium constant for following reaction? CaCO3 (s) CaO(s) + CO2 (g) [Ca01 ICO2 (l [CaCO3(1 3 (s)

10. Write Expression for equilibrium constant for following reaction? CaCO3 (s) CaO(s) + CO2 (g) [Ca01 ICO2 (l [CaCO3 (s)] = 1 3 (s) K- CO2 2 (g)

11. Write Expression for equilibrium constant for following reaction? CaCO3 (s) CaO(s) + CO2 (g) [Ca01 ICO2 (l [CaCO3 (sl [CaCO3 1 K- CO2 Units atm CO

12. CH3COOH CH3OH(

13. In a reaction b/n H2 and I2 at a certain temperature,the amounts of H2, I2 & HI at equilibrium were found to be 0.45 mole, 0.4 mole & 3.0 moles respectively in 2 It container. Calculate the equilibrium constant for the reaction at the given temp [Hal=0.45 [H2]=04 2 2 2

14. In a reaction b/n H2 and I2 at a certain temperature,the amounts of H2, I2 & HI at equilibrium were found to be 0.45 mole, 0.4 mole & 3.0 moles respectively in 2 It container. Calculate the equilibrium constant for the reaction at the given temp [H2l 0.45 [H21 04 2 2 2 Ans 50 HI] [H2] x [I21

15. For the reaction 2H1 H2 + 12 Initial conc. of HI is 8 M & at equilibrium 20% of HI dissociates to give H2 & I2 .Find out equilibrium constant? Initial 8 M At equilibrium

16. For the reaction 2HIH2 I2 Initial conc. of HI is 8 M & at equilibrium 20% of HI dissociates to give H2 & 12:Find out equilibrium constant? Initial 8 M At equilibrium 8 -1.6

17. For the reaction 2HIH2 I2 Initial conc. of HI is 8 M & at equilibrium 20% of HI dissociates to give H2 & 12:Find out equilibrium constant? Initial 8 M At equilibrium 8 1.6 0.8 0.8