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SG PRABU

2 years ago

to remember OPEC countries
AQUA VEIL SKIN
Angola
Qatar
UAE
Algeria
Venezuela
Equador
Iran
Libya
Saudi
Kuwait
Iraq
Nigeria

13

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Sakthi Prasanna

2 years ago

Thanks buddy.

Amruta Neelagar

2 years ago

AQUA LIVE SKIN

Vartika tiwari

2 years ago

thanksgiving

Farhan ansari

2 years ago

but there r 14 countries? including Gabon guinea!!

K

Komal

a day ago

Very nice and detailed explanation of the whole set of remainders. Thank you

0

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KC

Krishna Chaudhary

2 months ago

thanks sir

0

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Jitender Kumar

4 months ago

namaskar guru gi aapka koti koti maman

0

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Rajkumar Udit

4 months ago

Mst sir ek no.

0

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Master pranjal

8 months ago

Doubt qs :-
Q:- Find the remainder when (33^34)^35 is divided by 7?
Ans:-(33^34)^35/7
=33^N/7 where N=34^35
=(-2)^N/7 cyclicity=3
N÷3= 34^35/3 = (1)^35/3 this implies r=1 so
(-2)^1/7 this implies R=-2+7=5
remainder = 5 hona chahiye na but buk me rem.=4 Diya h.....
i don't understand Maine Kya glt Kiya h.......pls sir help me if I'm wrong....

0

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Mahesh Kumar Badige

8 months ago

your method is (-2)^N/7
this is wrong i think.
take +ve remainder there
ie, (5)^N/7 ===> rem= -1 for 3times
so cyclicity= 6
N÷6 ===> 34^35÷6 = 4^35÷6
===> 2^69/3 ==> (-1)^69 = -1+3=2 rem
now 5^2÷7 ===> rem = 4
is it clear now?

Master pranjal

8 months ago

ok..... I understand my fault....
Thanks bro

Mahesh Kumar Badige

8 months ago

is rem= 4 correct or not?
2^69/3===> (-1)^69= -1+3=2
but simplified by 2
so rem = 2×2 =4
now 5^4÷7 ==>625÷7 ==> rem=2
so required ans= 2

Master pranjal

8 months ago

no rem.=4 is the correct ans given in book

Mahesh Kumar Badige

8 months ago

but as per the procedure we have to consider simplification also

REMAINDER THEOREM ALL TYPES & THEOREMS COVERED WITH TRICKS

DON'T FORGET TO PRESS HIT LIKE FOLLOW RATE ENROLL/SAVE ASK YOUR DOUBTS IN COMMENTS

ALL TYPES & THEOREMS COVERED WITH TRICKS REMAINDER CLASS 14 THEOREM

Ump points R-1 ( Repetition tana) | Cyclicity! Cyclicity

affn twic Repetition wi stant the timus fos 2 3 time cyclicity= 6timu

3) 7S Method (133)5 121 7 2. tuy

Method 11 2 2. L4 6 oyclicity -3

M3 isy 7 2154 (29,2 23) S/ 7

QI(59) Find R 7

oI (s9) 28 find R P 28 28 3 3

2 3 2 3 3 3 3 3 9 3 3

32 32 x32 32x 32 x 32 Ram 3 2 24

23 23