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PYQ JEE Main 2019 Complex Numbers Part-1
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This lesson takes up questions of jee main 2019 in complex number part

## Vineet Loomba is teaching live on Unacademy Plus

Vineet Loomba
IITian | No. 1 Educator in IIT-JEE (Maths) | 4 Million Minutes Watch Time | 8+ Years Experience | Youtube: Maths Wallah | vineetloomba.com

U
6*2 = 12 days q liya.. wo bhi bata dena sir
N
Sir, jab aap alpha ka value put kiye hain to theta ka value 3pi/4 kaise liye hain
N
Nazar
22 days ago
que no 3 mai
sir 2nd qsn mei agr hum z+z bar =0 ka formula vul gye toh hum z Ko a+ib form mei lake arg = pi/2 (cz purely imaginary) kar sakte hei na?
sir 2nd qsn mei agr hum z+z bar =0 ka formula vul gye toh hum z Ko a+ib form mei lake arg = pi/2 (cz purely imaginary) kar sakte hei na?
sir 2nd qsn mei agr hum z+z bar =0 ka formula vul gye toh hum z Ko a+ib form mei lake arg = pi/2 (cz purely imaginary) kar sakte hei na?
sir 2nd qsn mei agr hum z+z bar =0 ka formula vul gye toh hum z Ko a+ib form mei lake arg = pi/2 (cz purely imaginary) kar sakte hei na?
1. JEE MAIN RANK BOOSTER COURSE COMPLEX NUMBERS FOR JEE MAIN AND ADVANCED PREPARED BY: ER. VINEET LOOMBA IITIAN IIT-JEE MENTOR

2. 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) ABOUT ME B. Tech. From IIT Roorkee IIT-JEE Mentor Since 2010. Youtube, Founder @ vineetloomba.com unacademy Many of my students are pursuing courses in IITs, NITs, BITs etc. Currently running my own Coaching Institute for JEE Main and Advanced Searh vineet loomba unacademy on GOOGLE

3. JEE MAIN RANK BOOSTER COURSE PREVIOUS YEAR QUESTIONS COMPLEX NUMBERS JEE MAIN 2019 PREPARED BY: ER. VINEET LOOMBA IITIAN IIT-JEE MENTOR

4. 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Example Let zo be a root of the quadratic equation x2 + x + 1 - 0. If z 36iz81 - 3i z3, then arg z is equal to (4) 6 (JEE Main 2019) 4 Sol. zo is a root of quadratic equation x2 +x 10 z 3 6i z81 - 3i z%3 3+3 arg(z)-tan-1/3) 3 T 3) 4 - SUCCESS IN JEE MAIN AND ADVANCED ER. VINEET LOOMBA (IIT ROORKEE)

5. 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Example Let A.{0e( , ) 1-2/m } 3 + 2i sin is purely imaginary Then the sum of the elements in A is (2) 6 3 4 2 (4) 3 (JEE Main 2019) (3 + 2, sin )(1+2i sine) + (3-2, sine)(1-2i sin ) 1+4sin2 Sol. Let z= 1-2i sin As z is purely imaginery, z +--0 sin2 - 4 =0 1-2, sin 1+2isin0 3' 3' 3 SUCCESS IN JEE MAIN AND ADVANCED ER. VINEET LOOMBA (IIT ROORKEE)

6. 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Example Let and be two roots of the equation x2 + 2x + 2 = 0, then 15 + 15 is equal to (1) -512 (3) 256 (2) 512 (4) -256 (JEE Main 2019) -2+4-8 2 Sol. x- Let =-1+i, =-1 -i i5 15 3 15 ) 3 ) 15 . 2cos 14 2(J2)"--256 SUCCESS IN JEE MAIN AND ADVANCED ER. VINEET LOOMBA (IIT ROORKEE)

7. 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Example Let z-|-+-| + If R(z) and /(z) respectively denote the real and imaginary parts of z, then (2) R(Z) 0 and /(Z) >0 (3) R(z) < 0 and /(Z) >0 (4) R(z)3 (JEE Main 2019) 6 (z)0, Re(z) V3 Option (1) is correct SUCCESS IN JEE MAIN AND ADVANCED ER. VINEET LOOMBA (IIT ROORKEE)

8. 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Example Let z, and z2 be any two non-zero complex numbers such that 312l1 - 41z2j. f z- 35272 such that 31z1 = 4| lf z = 34 + 24 then then 2z2 3z1 (2) 1 (4) Re(z)0 (1) Im(z)=0 2 JEE Main 2019 (BONUS QUES) (3) z1 322 4 222 321 2/2 3 ri =->_ (cos(0-0) + i sin(0-0)) + slls 5 2 x-[cos(0-0) + i sin(9-0)] 2 SUCCESS IN JEE MAIN AND ADVANCED ER. VINEET LOOMBA (IIT ROORKEE)

9. 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Save Save for this Course (Free) Recommend Lessons (Like) E M AND ADvANCED Rate and Review the Course Comments Sharing with friends MOST IMPORTANT QUESTIONS IN MATHEMATICS PREPARED ER. VINEET LOOMS MADE EASY 1ITIAN I IT-IEE MENTOR 00:00 05:46 SURE SHOT SUCCESS IN JEE MAIN AND ADVANCED CIIT-IEE) 91 likes 18 comments AO Share HINDI Crash Course Maths (Hindi) Most Important Questions in IIT-JEE Mathematics (Chapter- Wise) Vineet Loomba 11k Followers Follow 5.0 (51 ratings) Edit review SUCCESS IN JEE MAIN AND ADVANCED ER. VINEET LOOMBA (IIT ROORKEE)