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Problem Set - 2
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In this lesson, a case where tabular format conversion is required, have been explained.

Riya Agarwal is teaching live on Unacademy Plus

Riya Agarwal
Mostly, all DILR topics are covered for all aptitude exams. Use code "IRIYAAGARWAL" for discount on plus course.

U
Unacademy user
Please say about math practice.
mam bad widget 25 how
can you make videos on previous years caselets questions?
ma'am Kya aap apna yeah course hindi me bana sakte h .
Riya Agarwal
a year ago
Hindi me hai already. Data Interpretation (in Hindi) bolke course me.
  1. Data Intenpretation Based on Caselets Problem Set


  2. About Me . I hold a B.E degree in Electronics & Communication Engineering. . CAT, 17: DI & LR-98.29 %ile. . I would take you through the DI & LR lessons for CAT. . Not all are born Einstein's but trust me with hard work and dedication we can together make it possible.


  3. Kev Skills Involved I Firstly, identify the variables in the data, the number of instances of the variables provided and the respective inter relationships amongst the variables II. Once the above information is figured out, it can be put into a tabular format to solve the given case. III. Now fill the table with direct data given. Now, with the basic framework, identify the solution to the question being asked. Only focus to solve only to get the answer ofthe question asked NOTE: Transfer any information derived in the process of solving one question onto the table so that it is available for all subsequent questions.


  4. Caselet I: Directions: Ramesh has to decide whether or not to test a batch of 1000 widgets before sending them to the buyer. In case he decides to test, he has two options: (a) Use test I (b) Use test II Test I cost Rs. 2 per widget. However, the test is not perfect. It sends 20% of the bad ones to the buyer as good Test II costs Rs. 3 per widget. It brings out all the bad ones. A defective widget identified before sendingcan be corrected at a cost of s. 25 per widget All defective widgets are identified at the buyer's end and penalty of Rs. 50 per defective widget has to be paid by Ramesh


  5. Solution Let the total number of bad widgets be The total number of good widgets 1000 lfhe takes test I, his total cost will be = Rs. 2(1000) + 25 X 0.8r + 50 X 0.2g If he takes test 11, his total cost will be : Rs. 3(1000) + 25 X 96 Penalty if not tested = 50 X36 According to the conditions given, we have chart out the table with formulae's to solve the given questions DEFECTIVE WIDGETS PENALTY (if not tested) TEST I TEST II 2000+302 300025* 50*


  6. Answer the following: Q1. Ramesh should not test if the number of bad widgets in the lot is: (a) less than 100 (b) more than 200 (c) between 120 & 190 (d) Cannot be found out Workspace:


  7. Answer the following: Q1. Ramesh should not test if the number of bad widgets in the lot is: (a) less than 100 (b) more than 200 (c) between 120 & 190 (d) Cannot be found out. Workspace: Testing will be worth if the cost of testing is less than the cost of penalty levied on the defective pieces. In order to figure out the answers, let us chart out all the options given in the answer options and build a table for the given values: From the table, it is clear that for the number of defectives more than 100, the cost of testing is cheaper than the penalty. For 100 defectives, the cost of penalty is the same as that for testing. It is obvious that for number of defectives above 100 cost of any testing 100 is cheaper than the penalty. Thus, below 100 120 defectives, the penalty cost is will less than the cost of testing and hence, it is not worth testing DEFECTIVE WIDGETS PENALTY (if not tested) TEST I TEST II 200030 5000 5600 7700 8oo0 3000 + 25* 5500 6000 7750 8000 503 5000 6000 9500 10000 190 200


  8. Answer the following: Q2. If there are 120 defective widgets in the lot, Ramesh: (a) should either use Test I or not test (b) should either use Test II or not test (c) should use Test I or Test II. (d) should use Test I only. Workspace:


  9. Answer the following: Q2. If there are 120 defective widgets in the lot, Ramesh: (a) should either use Test I or not test (b) should either use Test II or not test (c) should use Test I or Test II (d) should use Test I only. Workspace: DEFECTIVE WIDGETS PENALTY (if not tested) TEST I TEST II From the table, derived in Q1 For 120 defectives, Cost of Test I < Cost of Test II Answer: Option (d) 2000+303 3000 + 25* 503 100 120 190 200 5000 5600 7700 8000 5500 6000 7750 8000 5000 6000 9500 10000


  10. Answer the following: Q3. If the number of defective widgets in the lot is between 200 and 400, Ramesh (a) may use Test I or Test II (b) should use Test I only. (c) should use Test II only (d) cannot decide. Workspace: