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Previous Year 2018 Part 4
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Harpreet Kaur
Youtube channel Preparation Point https://www.youtube.com/channel/UCC2_Jv4ThsDf5wUoxh_-LKw

U
Unacademy user
why should we consider square of modulus,will not modulus itself be sufficient?
Shivam PARASHAR
7 months ago
See,in quantum the particle(which we intended to find )is spread all over the space .so what we do ,we start confining our space to
Shivam PARASHAR
7 months ago
Confining our space(i.e normalisation) to get the max probability
Shivam PARASHAR
7 months ago
Or more specific -probability density i.e modulus square
Shivam PARASHAR
7 months ago
For example - |x| graph is like-. \|/ ie you get values in both postive and negative
Shivam PARASHAR
7 months ago
But if you square it - you will only get +ve values thus confine the space more and increase the chances of finding the particle
Akila N
7 months ago
In mod x how do we get negative values sir.. and if its squared the number is large eg. probability 5 would be better confined than 25 right..sorry i did not get..can u pls elaborate?thank u
Shivam PARASHAR
7 months ago
Soory i m unable to get you full comment
Shivam PARASHAR
7 months ago
Their is something wrong with this comments section
Shivam PARASHAR
7 months ago
Still i had read first two lines
Shivam PARASHAR
7 months ago
Yes you are right .. mod x square has larger values ..that means strong possibility of finding the particle
Shivam PARASHAR
7 months ago
Connect me on some other platform!!?!
Akila N
7 months ago
if you could leave mail id;I shall mail to it
Shivam PARASHAR
7 months ago
parasharshivam255@ymail.com
Akila N
6 months ago
thank u sir
1. Solution of CAT 2018-2017 unacademy By:- Harpreet Kaur PROFILE LINK https://unacademy.com/user/harpreet9504

2. Q:- Two straight lines intersect at a point O. Points Aj, A2, A ,.A are Bn on the other . If taken on one line and points B,, B,, B3, the point O is not included, the number of triangles that can be drawn using these points as vertices, is? Sol:- To tal As Az mtm 6u 3

3. Q:- A group of workers was put on a job. From the second day onwards, one worker was withdrawn each dav. The iob was finished when the last worker was withdrawn. Had no worker been withdrawn at any stage, the group would have finished the job in 55% of the time. How many workers were there in the group '? Sol:- 1st da n nn its then n-z , n- 3 Total Units - Ci 2 +3+ Hncl daj - n- 4, 3, 2, 1

4. Q:- A group of workers was put on a job. From the second day onwards, one worker was withdrawn each dav. The iob was finished when the last worker was withdrawn. Had no worker been withdrawn at any stage, the group would have finished the job in 55% of the time. How many workers were there in the group '? Sol:- |J no one left then 1 da wah's nnnits One daq worh 55%ofn n+1 =