Numerical on Circular Motion Part 5 (in Marathi)

Lesson 5 of 5 • 2 upvotes • 9:05mins

Akshay Gole

1. The angular displacement of a particle is given by Theta = 6t^2− 4t + 6, where time ‘t’ is in second and (theta) is in rad. The angular acceleration of particle at t = 4 sec is .... 2. The angular displacement of a particle is given by Theta = 5t^3 + 10t^2 − 2t + 3, where time ‘t’ is in second and theta is in rad. The angular acceleration of particle at t = 3 sec will be,