## Vineet Loomba is teaching live on Unacademy Plus

IIT-JEE VIDEO COURSE FOR SURE SHOT SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) IIT-JEE MATHS MADE EASY PREPARED BY: ER. VINEET LOOMBA IITian | IIT-JEE MENtOR Search vineet loomba unacademy" on GOOGLE

REVISION COURSE FOR JEE MAIN AND ADVANCED (IIT-JEE) ABOUT ME B.Tech. From IIT Roorkee IIT-JEE Mentor Since 2010 Doubts/Feedback in Comment Section * Comment other topics you want to revise. Follow me @ https://unacademy.com/user/vineetloomba to get updates or search me on Google * Share among your peers as SHARING is CARING!!

APPLICATION OF DERIVATIVES JEE MAIN AND ADVANCED IIT-IEE MATHS MADE EASY PREPARED BY: ER. VINEET LOOMBA IITiAN | IIT-JEE MENTOR FoR SURE SHoT SUcCESS IN JEE MAIN AND ADVANCED (IIT-JEE)

FOR 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) ENROL for this Course (Free) Enroll 439 Recommend Lessons (Like) E . Rate and Review the Course .Comments . Sharing with friends 15 1. 68 26 ratings 7 reviews Share MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKEE)

FOR 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Course Highlights: Concepts explained in easiest possible way * In-Chapter solved examples for Strong Foundation Coverage of Previous Year Questions of JEE Main and Advanced. Special Short Tricks for JEE Main and Advanced Daily Practice Problems * 100% Success with Minimal Effort Personalized Video Lectures (Comment Section) No Fake Promises, No long talks-only to the point information. MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKEE)

FOR 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Topics to be covered: Rate Measure O Monotonicity: Increasing Decreasing Functions O Geometrical interpretation of the derivative, Equations of Tangents and Normals Maxima and Minima along maximum and minimum values of a function. Significance of Second Order Derivative: Convexity and concavity. Miscellaneous Topics (As per your requirements) MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKEE)

FOR 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Syllabus coverage: JEE Main JEE Advanced BITSAT CBSE BOARDS MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKEE)

FOR 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Target Audience: . Class 12 students . Droppers JEE Main and Advanced Aspirants . Engineering Aspirants Mathematics Lovers MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKEE)

FOR 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) HOW TO STUDY THIS COURSE FOR BEST RESULTS ' Keep a Pen and Paper with you Pause Video and solve examples yourself . Make Short Notes . Regular Revision . Practice from Assignments/DPPs . Ask Doubts MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKEE)

FOR 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Other Detailed Courses Made so far on Unacademy: Strategy for IEE Main and Advanced Sets, Relations and Functions Trigonometry VLimits, Continuity Differentiability V Indefinite Integration V Complex Number V Logarithmic Functions Upcoming Courses in this month: >Permutations and Combinations As Required by you all (Comment) MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKEE)

FOR 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Example 1 Find the rate of change of the area of a circle per second with respect to its radius r when r 5 cm Solution The area A of a circle with radius r is given by A- of change of the area A with respect to its radius r is given by a. Therefore, the rate dA d, dr dr dA When r5 cm = 10 . Thus, the area of the circle is changing at the rate of dr 10 cm3/s. MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKEE)

FOR 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) If a particle is moving such that the velocity acquired is proportional to the square root of the distance covered, then its acceleration is (1) a constant Ex Sol.(1) Let v be the velocity of the particle when the distance covered is s. Then voc given = constant - .. The acceleration is constant MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKee)

FOR 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Ex Side of an equilateral triangle expands at the area of 2 cm/s The rate of increase of its area when each side is 10 cm is (1) 10 v2 cm2/sec 210 V2 cm2/sec (3) 10 cm2/sec (4)5 cm/sec Sol. (2) Let x be the side and A be the area of equilateral triangle at time t. Then 3 4 3 dx 2 dt dA dA dt 2 dx dt 10 2 103 x-10 and 2 MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKee)

FOR 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) ABOUT ME B.Tech. From IIT Roorkee IIT-JEE Mentor Since 2010 Doubts/Feedback in Comment Section * Comment other topics you want to revise. Follow me @ https://unacademy.com/user/vineetloomba to get updates. * Share among your peers as SHARING is CARING!!