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Introduction (in HIndi)
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Overview of the course

Vikas Joshi
Consultant at Capgemini, Inquisitive in nature, PGDM from FSM, Delhi. Love to teach. Can discuss anything under the sun.

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1. NTSE 2017 FULLY SOLVED By Vikas Joshi Educator Unacademy

2. About Me B.Techin Computer Science Engineering Worked for Salesforce, Cognizant. C.E.O. Sagacious Infotech. .PGDM from FSM, New Delhi. Reading enthusi Loves to teach. Can discuss anything under the sun. ast. .

4. PHYSICS A car covers 30 km at-a uniform speed of 60 km/hr. and the next 30 km at a uniform speed of 40 km/hr. The total time taken is (A) 30 min 1. (B) 45 miin (C) 75 min (D) 120 min Sol. (C) Total time = +72 30km 60km/hr 30km 40 n / hr T = 75 min

5. 2. A stone is own upwards with a speed "u" from the top of a tower. It reaches the ground with a velocity "3u" The height of the tower is 211 li (A) Sol. (D) Given 3U a-g

6. 9112-11-=-2gH 8u- -4u2 .:. -ve sign indicates the downward direction of displacement

7. When the speed of a particle is doubled, the ratio of its kinetic energy to its momentum: (A) remains the same (C) becomes half 3. (B) gets doubled (D) Becomes four times Sol. (B) Given Let initial speed u Initial momentum. (P) = mu Initial K.E.-1/2 mu- miu KE P Ratio of K. E. and P = miu lt Initial Ratio = 2 Final speed 2u Final momentum (P) = m(2n) = 277111 Final KE -m(211)-=-m x 41,-=2"m KE 2mu2 P 2miu Final ratio of-=- 11 Final Ratio = u Final Ratio of KE and P is double that of initial ratio

8. 4. Calculate the wavelength of radio waves of frequency 109 Hz. The speed of radio waves is 3 x 10s ms. (A) 60 cm (B) 40 cm (C) 30 cm (D) 10 cm Sol. (C) C=US C-3x10 m/s u=109 H= 3x108 = 109 109 10 10 3x100c,n = 10 30cm =

9. 5. A force of 16 N is distributed uniformly on one surface of a cube of edge 8 cm. The pressure on this surface is: (A) 3500 Pa (B) 2500 Pa (C) 4500 Pa (D) 5500 Pa Sol, (B) Force = 16M edge length= 8 cm Area of surface of cube-8cm x 8cm Area of cube 64 cm 64 2 10000 F 161 P 64 x 10 A 64x10- 4x104 =10000