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HOW TO FIND ACCELERATION WHEN V= 4t^3 − 2t ?
Lesson 7 of 7 • 0 upvotes • 10:35mins
Akshay Gole
A body starts from origin and moves along ‘x’ axis, at any instant velocity V = 4t^ 3 − 2t. Find acceleration when it is 2m from origin.
(Marathi) Class 11: Motion in a Plane
7 lessons • 1h 9m
1
Numerical on Motion in a Plane Part 1 (in Marathi)
9:19mins
2
Numerical on Motion in a Plane Part 2 (in Marathi)
11:34mins
3
Numerical on Motion in a Plane Part 3 (in Marathi)
11:31mins
4
Numerical on Motion in a Plane Part 4 (in Marathi)
10:54mins
5
Numerical on Motion in a Plane Part 5 (in Marathi)
7:52mins
6
Numerical on Motion in a Plane Part 6 (in Marathi)
7:49mins
7
HOW TO FIND ACCELERATION WHEN V= 4t^3 − 2t ?
10:35mins
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