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GATE 2018 all Thermodynamic questions solution of morning slot.Set 1 (in Hindi)
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In this lesson we will solve GATE 2018 all Thermodynamic questions of morning slot.

Rutuja Bothara
Strengthen GATE /PSU/ESE/SSC JE/RRB JE /campus Placements preparation. A passionate mechanical engineer -VIT University

Unacademy user
Sir I have confusion in second example what is difference in first and second sum.
Thank you so much!
Rutuja Bothara
5 months ago
Thanks
  1. GATE Previous years Thermodynamics questions GATE 2018 Thermodynamics solved questions set 1 By Rutuja Bothara


  2. RUTUJA BOTHARA . Perusing B.Tech in Mechanical Engineering from Vellore Institute of Technology, Vellore. (2015-2019) Cleared JEE Mains 2015 Cleared VITEEE-2015 with AIR 8718 . Cracked HITSEEE-2015 with AIR 91 Worked as a Career Counsellor in Teachers Academy . (2016- 2018) and BOLO app. https://unacademy.com/user/rurutujajb96-9511


  3. Which one of the statements is correct for a 1. lts pressure is less than saturation pressure at a given 2. Its temperature is less than saturation temperature at superheated vapour? temperature. a given pressure. given temperature. at a given pressure. 3. Its volume is less than volume of saturated vapour at a 4. Its enthalpy is less than enthalpy of saturated vapour


  4. and x=v-v, v=xy + (1-x) snie and x h=xh + (1-X) h fg and x = s-sf s 19 s x Sd(1-x) s and x = u-uf u=xugt (1-x)uf


  5. Sup-Cooled Liquid Flashing point Imaginary Saturated Curve T 50 F T 40F Super-Heated Gas T-30F T-20 F 0. T 10F Transition State Enthalpy Its pressure is less than the saturation pressure at a given temperature


  6. An ideal gas undergoes a process from state 1 (T1 = 300 K, p1 = 100 kPa) to state 2 ( T2 600 K, p2 500 kPa). The specific heats of the ideal gas are Cp 1kJ/kg-K and Cv -0.7k)/kg-K The change in specific entropy of the ideal gas from state 1 to state 2 (in kj/kg-K) is IS (correct to two decimal places)


  7. chaun ge in ehtropy is Pi R= Cp-Cv Pi 3 0o lOo


  8. A tank of volume 0.05 m/s3 contains a mixture of saturated water and saturated steam at 200 C The mass of the liquid present is 8 kg The entropy (in k]/kg K) of the mixture is (correct to two decimal places) Property data for saturated steam and water are: At 200 o C,psat 1.5538 MPa vf 0.001157 m3 /kg, vg 0.12736 m3 /kg sfg 4.1014 k]/kg K, 2.3309 sf kJ/kg K


  9. ae= mg 2dryness Fracton


  10. Volame of iquid 8x 0.001157 Vf = o.oog25@m 1.S Volume of vapo ' VqO.OS.00g2SG 9


  11. Steam flows through a nozzle at a mass flow rate of m=0.1 kg/s with a heat loss of 5 kW. The enthalpies at inlet and exit are 2500 kJkg and 2350 kJkg respectively. Assuming negligible velocity at inlet (C, 0), the velocity (C:) of steam(in m/s at the nozzle exit is (correct to two decimal places),. Q = 5kW h,2500 kJ/kg Ci-o- > m 0.1 kg/s h,-2350 kJ/kg C2


  12. An engine working on air standard otto cycle is supplied with air at 0.1 MPa and 35'C. The compession maio is 8. The heat suppied is 500 KJkg Property data c,1005JkgK c,-0.718kJkgK, R-0287kJ/kgK. The maximum tamperature (in K) of the cycle is


  13. Thank You For watching!! RATE REVIEW RECOMMEND