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GATE 2014 all thermodynamic questions solutions of morning slot (set 1) Hindi
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In this lesson we will discuss all GATE 2014 thermodynamic questions solutions of morning slot (set 1)

RUTUJA Bothara
Strengthen GATE /PSU/ESE/SSC JE/RRB JE /campus Placements preparation. A passionate mechanical engineer -VIT University

Unacademy user
sir in ques 57 why we taking 4×4=16 we can calculate no. of indpendent variables by using formula n(n-1)÷2 ??
  1. GATE Previous years Thermodynamics questions GATE 2014 Thermodynamics solved questions set 1 By Rutuja Bothara

  2. RUTUJA BOTHARA . Perusing B.Tech in Mechanical Engineering from Vellore Institute of Technology, Vellore. (2015-2019) e Cleared JEE Mains 2015 Cleared VITEEE-2015 with AIR 8718 Cracked HITSEEE-2015 with AIR 91 . Worked as a Career Counsellor in Teachers Academy (2016- 2018) and BOLO app. 9511

  3. The maximum theoretical work obtainable, when a system interacts to equilibrium with a reference environment, is called (A) Entropy (B) Enthalpy (C) Exergy (D) Rothalpy

  4. In a power plant, water (density 1000 kg/m3) is pumped from 80 kPa to 3 MPa. The pump has an isentropic efficiency of 0.85. Assuming that the temperature of the water remains the same, the specific work (in kJ/kg) supplied to the pump is (A) 0.34 (B) 2.48 (C) 2.92 (D) 3.43

  5. Actual specific pump work is W= V 2

  6. 1.5 kg of water is in saturated liquid state at 2 bar (Vf 0.001061 m3/kg, uf 504.0 kJ/kg, hf- k]/kg). Heat is added in a constant pressure process till the temperature of water reaches400 C (V1.5493 m3/kg, u 2967.0 k]/kg, h 3277.0 kJ/kg). The heat added (in k]) in the process is

  7. Heat addition at constant pressure g= 1.5 (3273-sos) 4158 KT

  8. In an air-standard Otto cycle, air is supplied at 0.1 MPa and 308 K. The ratio of the specific heats (Y) and the specific gas constant (R) of air are 1.4 and 288.8 J/ kg.K, respectively. If the compression ratio is 8 and the maximum temperature in the cycle is 2660 K, the heat (in k]/kg) supplied to the engine is

  9. Heat supplied 3 (Ts-Ta) = mcv 2. -' For-2 o.4 Na. o-4

  10. Ts-Ta x (366-30)

  11. T2 = 800k =2k For reversible heat engine