GATE Previous years Thermodynamics questions GATE 2014 Thermodynamics solved questions set 1 By Rutuja Bothara

RUTUJA BOTHARA . Perusing B.Tech in Mechanical Engineering from Vellore Institute of Technology, Vellore. (2015-2019) e Cleared JEE Mains 2015 Cleared VITEEE-2015 with AIR 8718 Cracked HITSEEE-2015 with AIR 91 . Worked as a Career Counsellor in Teachers Academy (2016- 2018) and BOLO app. https://unacademy.com/user/rurutujajb96- 9511

The maximum theoretical work obtainable, when a system interacts to equilibrium with a reference environment, is called (A) Entropy (B) Enthalpy (C) Exergy (D) Rothalpy

In a power plant, water (density 1000 kg/m3) is pumped from 80 kPa to 3 MPa. The pump has an isentropic efficiency of 0.85. Assuming that the temperature of the water remains the same, the specific work (in kJ/kg) supplied to the pump is (A) 0.34 (B) 2.48 (C) 2.92 (D) 3.43

Actual specific pump work is W= V 2

1.5 kg of water is in saturated liquid state at 2 bar (Vf 0.001061 m3/kg, uf 504.0 kJ/kg, hf- k]/kg). Heat is added in a constant pressure process till the temperature of water reaches400 C (V1.5493 m3/kg, u 2967.0 k]/kg, h 3277.0 kJ/kg). The heat added (in k]) in the process is

Heat addition at constant pressure g= 1.5 (3273-sos) 4158 KT

In an air-standard Otto cycle, air is supplied at 0.1 MPa and 308 K. The ratio of the specific heats (Y) and the specific gas constant (R) of air are 1.4 and 288.8 J/ kg.K, respectively. If the compression ratio is 8 and the maximum temperature in the cycle is 2660 K, the heat (in k]/kg) supplied to the engine is

Heat supplied 3 (Ts-Ta) = mcv 2. -' For-2 o.4 Na. o-4

Ts-Ta x (366-30)

T2 = 800k =2k For reversible heat engine

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RUTUJA Bothara

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Deepika Pathak

6 months ago

sir in ques 57 why we taking 4×4=16
we can calculate no. of indpendent variables by using formula n(n-1)÷2 ??

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