to enroll in courses, follow best educators, interact with the community and track your progress.
Enroll
1k
Examples on Mixed Concepts (in Hindi)
1,165 plays

More
This lesson takes up various examples covering different type of problems for areas using integration

## Vineet Loomba is teaching live on Unacademy Plus

Vineet Loomba
💥IITian | Top Educator 💥All Maths Chapters Complete & FREE 💥10+ Years Experience 💥Youtube: Maths Wallah 💥DPPs @ vineetloomba.com

U
NG
very good explanation
Sir please do the rest chapters of physics also.
Jm
sir can you plz make a lesson on how make graph of any curve for area under curve
Vineet Loomba
10 months ago
Already covered tht in graph transformation
very easy and simple
Sir the course is complete right ?
Vineet Loomba
a year ago
Yes ..theory is complete
Thank you
1. APPLICATIONS OF INTEGRALS (AREA UNDER CURVES) JEE MAIN AND ADVANCED IIT-IEE MATHS MADE EASY PREPARED BY: ER. VINEET LOOMBA IITiAN | IIT-JEE MENTOR FoR SURE SHoT SUcCESS IN JEE MAIN AND ADVANCED (IIT-JEE)

2. FOR 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) ABOUT ME B.Tech. From IIT Roorkee IIT-JEE Mentor Since 2010 Doubts/Feedback in Comment Section * Comment other topics you want to revise. Follow me @ https://unacademy.com/user/vineetloomba to get updates or search me on Google * Share among your peers as SHARING is CARING!!

3. FOR 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Illustration The area bounded by y x 4 and x y 2 is: 75 100 125 150 (B) 6 (C) 6 SOLUTION: (C) After drawing the figure, let us find the points of in- tersection of 125 =2x5--(4-9)--(8+27) + 4(5)-- x=-3,2 As(-3,5) and Bs(2,0) Shaded area, = | | (2-x)-(x2-4) | dr MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKee)

4. FOR 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Example : Find area bounded by y = 4-x, x-axis and the lines x = 0 and x = 2. Sol: By using the formula of Area Bounded by the x axis, we can4 obtain Required Area. 2 0 0 2 8 16 = | 4x--| = 8--=-sq. units 0 MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKEE)

5. FOR 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Example Find the area of the region enclosed by y = sin x, y = cos x and x-axis, 0 sx . 2 ea Sol: Find point of intersection is P. Therefore after obtaining the co-ordinates of P and then integrating with appropriate limits, we can obtain required Area. Hence, P is Required area 4 2 t/2 = 2--/2 sq. units At point of intersection P x =-as ordinates of y = sin x and ; y cos x are equal 4 MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKee)

6. FOR 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Illustration Using the method of integration, find the area of the region bounded by lines: 2x y 4, 3x- 2y =6and x-3y + 5 = 0 (JEE ADVANCED) Given equation of the lines are 2x + y = 4 3x-2y = 6 x- 3y5 0 Solving (i) and (i), we get (2, 0) Solving (i) and (ii), we get (4, 3) Solving) and (ii), we get (1, 2) (iii) (4,3) 4(3x-6 .: Required AreaX+5 2,0) ! (8 +20)--+5||-[(8-4)-(4-1)]-124-24)-(6-12)] -sq. units. MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKee)

7. FOR 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Enroll 934 ENROL for this Course (Free) Recommend Lessons (Like) E Rate and Review the Course ** 15 68 153 ratings - 30 reviews .Comments . Sharing with friends Share MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKEE)