## Vineet Loomba is teaching live on Unacademy Plus

APPLICATIONS OF INTEGRALS (AREA UNDER CURVES) JEE MAIN AND ADVANCED IIT-IEE MATHS MADE EASY PREPARED BY: ER. VINEET LOOMBA IITiAN | IIT-JEE MENTOR FoR SURE SHoT SUcCESS IN JEE MAIN AND ADVANCED (IIT-JEE)

FOR 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) ABOUT ME B.Tech. From IIT Roorkee IIT-JEE Mentor Since 2010 Doubts/Feedback in Comment Section * Comment other topics you want to revise. Follow me @ https://unacademy.com/user/vineetloomba to get updates or search me on Google * Share among your peers as SHARING is CARING!!

FOR 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Course Highlights: * Concepts explained in easiest possible way * In-Chapter solved examples for Strong Foundation Coverage of Previous Year Questions of JEE Main and Advanced. Special Short Tricks for JEE Main and Advanced Daily Practice Problems * 100% Success with Minimal Effort Personalized Video Lectures (Comment Section) MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKEE)

FOR 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Ilustration: Find the area bounded by the curve y sin2x, x-axis and the lines x and x = 4 t/ 2 3 /4 Solution Required area - sin 2xdx+ sin 2xdx /4 Tt/ 2 /2 3-4 3t/4 cos 2x ) /2 cos 2x 2 /2 2 2 MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKEE)

FOR 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) CoNCEPT 2 dy Cu y a NOTE rca on RHs axis ae ahue UXC moduls to make thew posiiv Re Ahea MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKee)

FOR 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Ex Find the ai sugcon bounded ul Sol 2. 3 MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKee)

FOR 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) LONCEPT 3 hea betwe #4 2A Anrawi nespeskive alwars bepositivc "cy 09H0 plane. MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKee)

FOR 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Illustration The area bounded by the curves y = r and r + = 2 above X-axis is : SOLUTION: (D) Let us first find the points ofintersection of curves. Solving y =x, and r -2 simultaneously, we get (x2-1)(x2 + 2) = 0 1 ) 2 4 3 3 2 A=(-1,0) and B=(1,1) sq. units. Shaded Area= +1W2-2-x2)dr MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKee)

FOR 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Enroll 934 ENROL for this Course (Free) Recommend Lessons (Like) E Rate and Review the Course ** 15 68 153 ratings - 30 reviews .Comments . Sharing with friends Share MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKEE)