MOMENTUM Momentum Impulse Conservation of Momentum in 1 Dimension Conservation of Momentum in 2 Dimensions Angular Momentum Torque Moment of Inertia

Momentum Defined p momentum vector m mass v velocity vector

Momentum Facts . Momentum is a vector quantity! Velocity and momentum vectors point in the same direction. . SI unit for momentum: kg m/s (no special name) Momentum is a conserved quantity (this will be proven later) .A net force is required to change a body's momentum. Momentum is directly proportional to both mass and speed. . Something big and slow could have the same momentum as something small and fast.

Momentum Examples 3 m/s 30 kg m/s . 10 kg 10 kg Note: The momentum vector does not have to be drawn 10 times longer than the velocity vector, since only vectors of the same quantity can be compared in this way. 260 P 45 kg m/s at 26 N of E

Equivalent Momenta Car: m 1800 kg; V 80 m/s p 144.105 kg m/s m = 9000 kg; v= 16 m/s p 1.44.105 kg. m/s Bus: Train: m 3.6.104 kg; V 4 m/s 0-1 .44 . 1 05 kg . m/s continued on next slide

Equivalent Momenta (cont.) The train, bus, and car all have different masses and speeds, but their momenta are the same in magnitude. The massive train has a slow speed; the low-mass car has a great speed; and the bus has moderate mass and speed. Note: We can only say that the magnitudes of their momenta are equal since they're aren't moving in the same direction. The difficulty in bringing each vehicle to rest--in terms ofa combination of the force and time required--would be the same, since they each have the same momentum.

Impulse Defined Impulse is defined as the product force acting on an object and the time during which the force acts. The symbol for impulse is J. So, by definition: Example: A 50 N force is applied to a 100 kg boulder for 3 s. The impulse of this force is J (50 N) (3 s) 150 N s. Note that we didn't need to know the mass of the object in the above example.

Impulse Units J= Ft shows why the SI unit for impulse is the Newton-second. There is no special name for this unit, but it is equivalent to a kg m/s proof:Ns 1 (kg m/s2) (s) 1 kg m/s Fnet ma shows this is equivalent to a newton Therefore, impulse and momentum have the same units, which leads to a useful theorem

Impulse Momentum Theorem The impulse due to all forces acting on an object (the net force) is equal to the change in momentum of the object: net ! We know the units on both sides of the equation are the same (last slide), but let's prove the theorem formally net l ma

Stopping Time Ft-Ft Imagine a car hitting a wall and coming to rest. The force on the car due to the wall is large (big F), but that force only acts for a small amount of time (little t). Now imagine the same car moving at the same speed but this time hitting a giant haystack and coming to rest. The force on the car is much smaller now (ittle F), but it acts for a much longer time (big t). In each case the impulse involved is the same since the change in momentum of the car is the same. Any net force, no matter how small, can bring an object to rest if it has enough time. A pole vaulter can fall from a great height without getting hurt because the mat applies a smaller force over a longer period of time than the ground alone would

Impulse - Momentum Example A 1.3 kg ball is coming straight at a 75 kg soccer player at 13 m/s who kicks it in the exact opposite direction at 22 m/s with an average force of 1200 N. How long are his foot and the ball in contact? answer: We'll use FnetAp. Since the ball changes direction, ap = ma v = m (y-vo) 12 -1.3 [22-(13) (.3 kg) (35 m/s) - 45.5 kg m/s. Thus, t 45.5/1200 - 0.0379 s, which is just under 40 ms During this contact time the ball compresses substantially and then decompresses. This happens too quickly for us to see, though. This compression occurs in many cases, such as hitting a baseball or golf ball.

Fnet Vs. t graph Fnet (N) Net area t (s) 6 A variable strength net force acts on an object in the positive direction for 6 s, thereafter in the opposite direction. Since impulse is Fnet t, the area under the curve is equal to the impulse, which is the change in momentum. The net change in momentum is the area above the curve minus the area below the curve. This is just like a v vs. t graph, in which net displacement is given area under the curve

Directions after a collision On the last slide the boxes were drawn going in the opposite direction after colliding. This isn't always the case. For example, when a bat hits a ball, the ball changes direction, but the bat doesn't. It doesn't really matter, though, which way we draw the velocity vectors in "after picture. If we solved the conservation of momentum equation (red box) for v, and got a negative answer, it would mean that m2 was still moving to the left after the collision. As long as we interpret our answers correctly, it matters not how the velocity vectors are drawn. mi m2

Sample Problem 2 35 g 7 kg 700 m/s Sume as the last problem excert ihis time it'sa block of wood ralher than buter and he bulle does not pass all the way through it. How fast do they move together after impact? 7. 035 kg (0.035) (700) 7.035 v V- 48 m/s Note: Once again we're assuming a frictionless surface, otherwise there would be a frictional force on the wood in addition to that of the bullet, and the "system" would have to include the table as well

Sample Problem 3 An apple is originally at rest and then dropped. After falling a short time, it's moving pretty fast, say at a speed V. Obviously, momentum is not conserved for the apple, since it didn't have any at first. How can this be? answer: Gravity is an external force on the apple, so momentum for it alone is not conserved. To make gravity "internal," we must define a system that includes apple the other object responsible for the gravitational force- Earth. The net force on the apple-Earth system is zero, and momentum is conserved for it. During the fall the Earth attains a very small speed v. So, by conservation of momentum: Earth

Sample Problem 4 A crate of raspberry donut filling collides with a tub of lime Kool Aid on a frictionless surface. Which way on how fast does the Kool Aid rebound? answer: Let's draw v to the right in the after picture. 3(10)-6(15) =-3(45) +15 V Since v came out negative, we guessed wrong in drawing v to the right, but that's OK as long as we interpret our answer correctly. After the collision the lime Kool Aid is moving 3.1 m/s to the left. before 10 m/s 6 m/s 3 Kg 15 kg after 4.5 m/s 3 kg 15 kg

Conservation of Momentum in 2-D To handle a collision in 2-D, we conserve momentum in each dimension separately. Choosing down & right as positive: before m2 m, 2 V. after: m2 ea Vi Cl Conservation of momentum equations:

Exploding Bomb Acme after before A bomb, which was originally at rest, explodes and shrapnel flies every which way, each piece with a different mass and speed. The momentum vectors are shown in the after picture. continued on next slide

Exploding Bomb (cont.) Since the momentum of the bomb was zero before the explosion, it must be zero after it as well. Each piece does have momentum, but the total momentum of the exploded bomb must be zero afterwards This means that it must be possible to place the momentum vectors tip to tail and form a closed polygon, which means the vector sum is zero. If the original momentum of the bomb were not zero, these vectors would add up to the original momentum vector.

Alternate Solution 40 Shown are momentum vectors (in g. m/s). The black vector is the total momentum before the collision Because of conservation of momentum, it is also the total momentum after the collisions. We can use trig to find its magnitude and direction. 5168 B 400 1500 Law of Cosines p 51682 15002-2.5168. 1500 cos 40 p 4132.9736 g m/s Dividing by total mass: V (4132.9736 g. m/s) (452 g) 9.14 m/s sin 40 4132.9736- Sin Law of Sines -13.49080 1500 Angle w/ resp. to horiz. 40 13. 4908 53.49

Angular Momentum Angular momentum depends on linear momentum and the distance from a particular point. It is a vector quantity with symbol L. If rand v are L then the magnitude of angular momentum w/ resp. to point Q is given by L = rp = mvr. In this case L points out of the page. If the mass were moving in the opposite direction, L would point into the page. The SI unit for angular momentum is the kg m2/s. (It has no special name.) Angular momentum is a conserved quantity. A torque is needed to change L just a force is needed to change p. Anything spinning has angular has angular momentum. The more it has, the harder it is to stop it from spinning.

Angular Momentum: General Definition If r and v are not L then the angle between these two vectors must be taken into account. The general definition of angular momentum is given by a vector cross product: L=r p This formula works regardless of the angle. As you know from our study of cross products, the magnitude of the angular momentum of m relative to point Q is: L = rp sing= m v r. In this case, by the right-hand rule, L points out of the page. If the mass were moving in the opposite direction, L would point into the page.

Moment of Inertia Any moving body has inertia. (It wants to keep moving at constant v.) The more inertia a body has, the harder it is to change its linear motion. Rotating bodies possess a rotational inertial called the moment of inertial, I. The more rotational inertia a body has, the harder it is change its rotation. For a single point-like mass w/ respect to a given point Q, 1 mr2. For a system, 1 the sum of each mass times its respective distance from the point of interest. I mr r.

Moment of Inertia Example Two merry-go-rounds have the same mass and are spinning with the same angular velocity. One is solid wood (a disc), and the other is a metal ring. Which has a bigger moment of inertia relative to its center of mass? Co answer: I is independent of the angular speed. Since their masses and radii are the same, the ring has a greater moment of inertia. This is because more of its mass is farther from the axis of rotation. Since 1 is bigger for the ring, it would more difficult to increase or decrease its angular speed

Torque & Angular Acceleration Newton's 2nd Law, as you know, is Fe ma The 2nd Law has a rotational analog: net-1 required for a body to undergo angular acceleration. A force is required for a body to undergo acceleration. A urning force" 95 (a torque)is The bigger a body's mass, the more force is required to accelerate it. Similarly, the bigger a body's rotational inertia, the more torque is required to accelerate it angularly Both m and / are measures of a body's inertia (resistance to change in motion).

Linear Momentum & Angular Momentum If a net force acts on an object, it must accelerate, which means its momentum must change. Similarly, if a net torque acts on a body, it undergoes angular acceleration, which means its angular momentum changes. Recall, angular momentum's magnitude is given by L mvr (if v and r are perpendicular) So, if a net torque is applied, angular velocity must change, which m changes angular momentum proof: Tnet tma So net torque is the rate of change of angular momentum, just as net force is the rate of change of linear momentum. continued on next slide

22 lessons,

3h 8m

Enroll

17

✕Download

Rohit Kumar Yadav

Author||Blogger||Photographer||Poet

Unacademy user

Anjali Singh

a year ago

awsome discription

0

Reply